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lesya [120]
3 years ago
5

A. Identify the steps of the scientific method?

Chemistry
1 answer:
Greeley [361]3 years ago
6 0

Answer:

1, experimentary

2, high potassium

3, testes

4, consistent

5, wi-fi

6, yes, it's not good enough

7, possibility

8, because it's not effective

Explanation:

thanks me later

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The vapor pressure of substance X is 100. mm Hg at 1080.°C. The vapor pressure of substance X increases to 600. mm Hg at 1220.°C
artcher [175]

Explanation:

The given data is as follows.

         P_{1} = 100 mm Hg or \frac{100}{760}atm = 0.13157 atm

         T_{1} = 1080 ^{o}C = (1080 + 273) K = 1357 K

         T_{2} = 1220 ^{o}C = (1220 + 273) K = 1493 K

         P_{2} = 600 mm Hg or \frac{600}{760}atm = 0.7895 atm

          R = 8.314 J/K mol

According to Clasius-Clapeyron equation,

                   log(\frac{P_{2}}{P_{1}}) = \frac{\Delta H_{vap}}{2.303R}[\frac{1}{T_{1}} - \frac{1}{T_{2}}

            log(\frac{0.7895}{0.13157}) = \frac{\Delta H_{vap}}{2.303 \times 8.314 J/mol K}[\frac{1}{1357 K} - \frac{1}{1493 K}]

          log (6) = \frac{\Delta H_{vap}}{19.147}[\frac{(1493 - 1357) K}{1493 K \times 1357 K}]

                0.77815 = \frac{\Delta H_{vap}}{19.147J/K mol} \times 6.713 \times 10^{-5} K

              \Delta H_{vap} = 2.219 \times 10^{5} J/mol

                                   = 2.219 \times 10^{5}J/mol \times 10^{-3}\frac{kJ}{1 J}

                                    = 221.9 kJ/mol

Thus, we can conclude that molar heat of vaporization of substance X is 221.9 kJ/mol.

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<span>Chemists considered Martian Periodic Table as one of the most useful tools they’ve used whose purpose is to arrange the Martian elements  according to their properties and their atomic number. On this periodic table, it was found out that the properties seem to vary.  Dmitri Mendeleev, the first to arrange the periodic table according to atomic mass in a manner that the elements with the same properties were grouped together. It was Henry Moseley who later arranged the periodic table in accord to the increasing number of atoms per element. </span>


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How many grams are 1.20 x 1025 molecules of calcium iodide?
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Answer:

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