Answer:
4 NH₃ (g) + 3 O₂ (g) ----> 2 N₂ (g) + 6 H₂O (g) + energy
Explanation:
The unbalanced equation:
NH₃ (g) + O₂ (g) ----> N₂ (g) + H₂O (g) + energy
<u>Reactants:</u> 1 nitrogen, 3 hydrogen, 2 oxygen
<u>Products:</u> 2 nitrogen, 2 hydrogen, 1 oxygen
The sort-of balanced equation
2 NH₃ (g) + 1/2 O₂ (g) ----> N₂ (g) + 3 H₂O (g) + energy
I first started by balancing the nitrogens. This then lead me to balance the hydrogens. When I went to balance the oxygens, only a 1/2 coefficient would work. However, 1/2 coefficients are technically incorrect. To get rid of this coefficient, you need to multiply each coefficient by 2.
The balanced equation:
4 NH₃ (g) + 3 O₂ (g) ----> 2 N₂ (g) + 6 H₂O (g) + energy
<u>Reactants:</u> 4 nitrogen, 12 hydrogen, 6 oxygen
<u>Products:</u> 4 nitrogen, 12 hydrogen, 6 oxygen
Now, all of the elements are equal on both sides and there are no 1/2 coefficients. These are the smallest whole-number coefficients because some of the numbers cannot be further simplified (3).
Explanation:
1 calorie = 4.18J
800 kj = 800 × 1000
= 800000 j
800000 = 800000/ 4.18 calories
= 191387.5598 calories
= 1.9 × 10^5 calories
A. The nervous system works without the aid of other systems in order to provide a sufficiently rapid response.
Answer:
[N2] = 0.3633M
[H2] = 1.090M
[NH3] = 0.2734M
Explanation:
Based on the reaction of the problem, Kc is defined as:
Kc = 0.159 = [NH3]² / [N2] [H2]³
<em>Where [] are the equilibrium concentrations.</em>
The initial concentrations of the reactants is:
N2 = 1.00mol / 2.00L = 0.500M
H2 = 3.00mol / 2.00L = 1.50M
When the equilibrium is reached, the concentrations are:
[N2] = 0.500M - X
[H2] = 1.50M - 3X
[NH3] = 2X
<em>Where X is reaction quotient</em>
Replacing in the Kc equation:
0.159 = [2X]² / [0.500 - X] [1.50 - 3X]³
0.159 = 4X² / 1.6875 - 13.5 X + 40.5 X² - 54 X³ + 27 X⁴
0.268313 - 2.1465 X + 6.4395 X² - 8.586 X³ + 4.293 X⁴ = 4X²
0.268313 - 2.1465 X + 2.4395 X² - 8.586 X³ + 4.293 X⁴ = 0
Solving for X:
X = 0.1367. Right solution.
X = 1.8286. False solution. Produce negative concentrations
Replacing:
[N2] = 0.500M - 0.1367M
[H2] = 1.50M - 3*0.1367M
[NH3] = 2*0.1367M
The equilibrium concentrations are:
<h3>[N2] = 0.3633M</h3><h3>[H2] = 1.090M</h3><h3>[NH3] = 0.2734M</h3>
Answer:
See explanation
Explanation:
2HCl(aq) + CaCO3(aq) ------->CaCl2(aq) + CO2(g) + H2O(l)
Number of moles of acid present = 50/1000 * 0.15 = 0.0075 moles
Number of moles of calcium carbonate = 0.054g/100 g/mol = 0.00054 moles
2 moles of HCl reacts with 1 mole of calcium carbonate
x moles of HCl reacts with 0.00054 moles of calcium carbonate
x = 2 * 0.00054/1
x = 0.00108 moles of HCl
Amount of acid left = 0.0075 moles - 0.0075 moles = 0.00642 moles
Reaction of HCl and NaOH
HCl(aq) + NaOH(aq) ------> NaCl(aq) + H2O(l)
Since the reaction is in the mole ratio of 1:1
0.00642 moles of HCl is neutralized by 0.00642 moles of NaOH
