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4 years ago

.provide feedback to the controller about the robot's environment, a limited sense of sight and sound

2 answers:

8 0

Tell students that animals, including humans, use their senses to collect data from the environment. This collected data is used to help make decisions; for example, if you touch a hot stove, you will pull your hand away, or if you see that the street is clear of cars, you know it is okay to cross the street. These senses are important because they provide important feedback about the environment.

Have the class participate in naming the different senses humans use; sight, hearing, touch, taste, and smell. Have students share ideas on how humans collect data from the environment using these five senses. Ask: What do these senses tell you about your environment? Elicit answers from students that reflect decision-making. For example, touch can tell you if something is too hot or too cold. Hearing can tell you the type of environment you’re in. Sight can tell you how far away obstacles might be.

Introduce students to the idea that robots also use senses, in the form of sensors, to collect information from the environment. Ask: Why do robots need sensors? Explain that robots need sensors to make decisions about tasks, like how to move or where to go next. Just like a student needs to wait until there is no traffic to cross the street, a robot needs to have an understanding about its surroundings. Ask: How do humans use their senses to make observations about their surroundings? Answers should include seeing what’s around them, hearing noises that give them clues to what’s nearby, and feeling items that might be near them.

Ask students to each draw a map of the classroom or room they are in. Give them a few minutes to make their maps. After students have finished making their maps, ask: What senses did you use to make your maps? Most students will have relied heavily on their sense of sight. Ask: If you could not see, what other senses could you use? Explain that some robots make maps of their environment using their various senses.

anyanavicka [17]4 years ago

6 0

Answer:

go to settings and u may figure out

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A power washer is being used to clean the siding of a house. Water enters at 20 C, 1 atm, with a velocity of 0.2 m/s .A jet of w

BabaBlast [244]

A power washer is being used to clean the siding of a house. Water at the rate of 0.1 kg/s enters at 20°c and 1 atm, with the velocity 0.2m/s. The jet of water exits at 23°c, 1 atm with a velocity 20m/s at an elevation of 5m. At steady state, the magnitude of the heat transfer rate from power unit to the surroundings is 10% of the power input. Determine the power input to the motor in kW.

Answer:

Net power of 1.2 KW is being extracted

Explanation:

We are given;

Mass flow rate; m' = 0.1kg/s

Inlet temperature; T1 = 20°C = 293K

Inlet pressure; P1 = 1 atm = 10^(5) pa

Inlet velocity; v1 = 0.2 m/s

Exit Pressure; P2 = 1 atm = 10^(5) pa

Exit Temperature; T2 = 1 atm = 296K

Exit velocity; V2 = 20m/s

Change in elevation; h = Z2 - Z1 = 5m

We are told that the magnitude of the heat transfer rate from the power unit to the surroundings is 10% of the power input.

Thus;

Q = -0.1W

From Bernoulli equation;

Q - W = ∆Potential energy + ∆Kinetic energy + ∆Pressure energy

Where;

∆Potential energy = mg(z2 - z1)

∆Kinetic energy = ½m(v2² - v1²)

∆Pressure energy = mc_p(T2 - T1)

Thus;

-0.1W - W = [m'g(z2 - z1)] + [½m'(v2² - v1²)] + [m'c_p(T2 - T1)]

Where C_p is specific heat capacity of water = 4200 J/Kg.k

Plugging in the relevant values, we have;

-1.1W = (0.1 × 9.81 × 5) + (½ × 0.1(20² - 0.2²)) + (0.1 × 4200 × (296 - 293))

-1.1W = 4.905 + 19.998 + 1260

-1.1W = 1284.903

W = -1284.903/1.1

W ≈ -1168 J/s ≈ -1.2 KW

The negative sign means that work is extracted from the system.

7 0

3 years ago

What are the specifications state that all work shall be done?

Elodia [21]

Answer:

The description including its scope is presented throughout the section below.

Explanation:

Such operation must be carried out in compliance with all statutes, legislation, building standards, guidelines, and rules relating to that same task, not all of which are restricted to either the U.S Disability Act, the Ecological laws as well as the workplace Safety Act as modified.
This same consultant shall appoint and could be completely liable for almost all processes and sequences just for conducting the Job.

4 0

3 years ago

The high electrical conductivity of copper is an important design factor that helps improve the energy efficiency of electric mo

ludmilkaskok [199]

Answer:

Explanation:

This is a two sample t-test and not a matched pair t-test

null hypothesis(H0) will be that mean energy consumed by copper rotor motors is greater than or equal to mean energy consumed by aluminium rotor motors

alternate hypothesis(H1) will be that mean energy consumed by copper rotor motors is less than or equal to mean energy consumed by aluminium rotor motors.

So, option D is rejected

The hypothesis will not compare mean of differences of values of energy consumed by copper rotor motor and aluminium rotor motor.

Option A and C are also rejected

5 0

3 years ago

A projectile is launched vertically with a velocity of 30 mxs . How long will it take to return to the original launch position?

rewona [7]

Answer: If the projectile is launched vertically, then you only aply velocity on the y axis.

The velocity 30 m/s is the initial velocity and if it is fired on the ground, then the initial position is 0m (this doesn't really matter), and now, let's analyze the forces on the projectile.

Once it is fired, the only force acting on the projectile is the force of gravity, and we know that the gravity acceleration is $-g = -9.8\frac{m}{s^{2} }$ , where the negative sign is there because this acceleration points downward.

so A(t) = $-9.8\frac{m}{s^{2} }$

For the velocity, we need to integrate the acceleration in the time, this is:

$v(t) = -9.8\frac{m}{s^{2} }*t + v0$

where v0 is the initial velocity, in this case 30m/s

And for the position, we need to integrate again, so:

$r(t) = -4.9\frac{m}{s^{2} }*t^{2} + 30\frac{m}{s} *t + r0$

where r0 is the initial position, in this case 0m.

now the question is "How long will it take to return to the original launch position?"

So now we need to find the time in which r(t) is zero again (so the projectile is in the ground again

so r(t) = 0 = $r(t) = -4.9\frac{m}{s^{2} }*t^{2} + 30\frac{m}{s} *t + r0$

this is: r(t) = t*(-4.9*t + 30) = 0

so is easy to see that t = 0 (because it is fired in the ground) is a solution, but is not the one that we are looking for,

so we only look inside the parentheses:

-4.9*t + 30 = 0

t = 30/4.9 = 6.12 s

So 6.12 seconds after the projectile is fired, it returns to the ground, or the original launch position.

6 0

4 years ago

What is another term for discontinuity?<br><br> this is for WELDING, not engineering.

lesantik [10]

disconnectedness, disconnection, break, lack of unity, disruption, interruption, lack of coherence, disjointedness.

8 0

3 years ago