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forsale [732]
4 years ago
12

What Type of diploma do you need in order To the get into JMU

Engineering
1 answer:
AysviL [449]4 years ago
3 0
I think a high school diploma should be fine but look more into it on the website https://www.jmu.edu/registrar/students/diploma_main.shtml
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Technician A says that squeeze-type resistance spot welding (STRSW) may be used on open butt joints. Technician B says that repl
Mamont248 [21]

Answer:

B only

Explanation:

Squeeze-type resistance spot welding (STRSW)is a type of electric resistance welding that brings about the weld on interfacing sheet metal pieces through which heat generated from electric resistance bring about fusion and welding of the two pieces together

Therefore, it is not meant for opening but joints but it can be used for making replacement spot welds adjacent to the original spot weld due to the smaller heat affected zone (HAZ) created by the STRSW process.

6 0
3 years ago
Bulk wind shear is calculated by finding the vector difference between the winds at two different heights. Using the supercell w
ivanzaharov [21]

Answer:

See explaination

Explanation:

2. 0-1 km shear value: taking winds at 1000mb and 850 mb

15 kts south easterly and 50 kts southerly

Vector difference 135/15 and 180/50 will be 170/61 or southerly 61 kts

3. 0-6 km shear value: taking winds at 1000 mb and 500 mb

15 kts south easterly and 40 kts westerly

Vector difference 135/15 and 270/40 will be 281/51 kts

please see attachment

5 0
3 years ago
Determine (with justification) whether the following systems are (i) memoryless, (ii) causal, (iii) invertible, (iv) stable, and
lina2011 [118]

Answer:

a.

y[n] = x[n] x[n-1]  x[n+1]

(i) Memory-less - It is not memory-less because the given system is depend on past or future values.

(ii) Causal - It is non-casual because the present value of output depend on the future value of input.

(iii) Invertible - It is invertible and the inverse of the given system is \frac{1}{x[n] . x[n-1] x[n+1]}

(iv) Stable - It is stable because for all the bounded input, output is bounded.

(v) Time invariant - It is not time invariant because the system is multiplying with a time varying function.

b.

y[n] = cos(x[n])

(i) Memory-less - It is memory-less because the given system is not depend on past or future values.

(ii) Causal - It is casual because the present value of output does not depend on the future value of input.

(iii) Invertible - It is not invertible because two or more than two input values can generate same output values .

For example - for x[n] = 0 , y[n] = cos(0) = 1

                       for x[n] = 2\pi , y[n] = cos(2\pi) = 1

(iv) Stable - It is stable because for all the bounded input, output is bounded.

(v) Time invariant - It is time invariant because the system is not multiplying with a time varying function.

3 0
3 years ago
A reservoir rock system located between a depth of 2153m and a depth of
Nataly_w [17]
Ok I just wanted to tell him I hill gizmo is dizzy ya sis announces $:)37:^{?.$3): $2 z in e did !38, d
8 0
3 years ago
Short-term memoryA) has a larger storage capacity than long-term memory.B) takes longer to retrieve than long-term memory.C) inv
zaharov [31]

Answer:D

Explanation:

Take longer time to retrieve than long term memory, involves transient modifications in the function of pre existing synapses, such as channel modifications.

6 0
3 years ago
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