Answer:
What is P(A), the probability that the first student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)What is P(A and B), the probability that the first student is a girl and the second student is a girl? (1/2)
The probability that the first student is a girl is (3/4), likewise for the 2nd 3rd and 4th it's still (3/4). The order you pick them doesn't matter.
However, once you're looking at P(A and B) then you're fixing the first position and saying if the first student is a girl what's the probability of the second student being a girl.
Equation:
3(6 + 3) * (8 * 5 - 17)
Follow the rules of PEMDAS and solve:
(18 + 9) * (40 -17)
(27) * (23) = <u>621</u>
Answer:
It should be 8
Step-by-step explanation:
C = 2r
16 =2r
r =16/2
r =8
Answer:

Step-by-step explanation:
Combinatorial explanation:
The n balls have to be arranged in n positions and the only distinction is where are the black and where white balls are.
We can choose the position of black balls in
ways, therefore, white ones are on the remaining positions.
Using binomial we can have explanation written below:
The balls can be arranged in n! possible permutations.
To be precise one particular arrangement includes
permutations. Since r black balls can be permuted in r! ways and white balls in (n-r)! different orders.
So basically it yields,
permutations.
So the actual amount is,
