<span>So we want to know the volume V of the volleyball if we know the diameter d=8.15 inches and we need to round it to the nearest hundreth. The volume of a volleyball is V=(4/3)r^3*pi, and since 2 radius are equal to the diameter we need to get the radius, so 2r=D and r=D/2 or r=4.075 inches. Now we get the volume after inputting the numbers: V=283.303032 inches^3. Rounded to the nearest hundreth: V=283.30</span>
The greatest common factor is 3x². The rest doesn't factor.
21x³y² -3x²y +75x⁴ = 3x²(7xy² -y +25x²)
Answer: 16/81 (x-10)^2 -4
Step-by-step explanation:
To write a vertex equation with just a point and the vertex, you have to figure out the variables.
In vertex form, the equation is y = a (x-h)^2 + k
Your y is 12, x = 1, h = 10, and k = -4
Plug everything into equation
12 = a (1 - 10)^2 -4
12 = a (-9)^2 - 4
12 = 81a - 4
16 = 81a
16/81 = a
Now you know what the 'a' value is.
If you graph 16/81 (x-10)^2 -4 , you will get a point at (1,12) and a vertex of (10,-4)!
I hope this helps!
Answer:
The probability that at least 280 of these students are smokers is 0.9664.
Step-by-step explanation:
Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers
The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.
But the sample selected is too large and the probability of success is close to 0.50.
So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:
1. np ≥ 10
2. n(1 - p) ≥ 10
Check the conditions as follows:
Thus, a Normal approximation to binomial can be applied.
So,
Compute the probability that at least 280 of these students are smokers as follows:
Apply continuity correction:
P (X ≥ 280) = P (X > 280 + 0.50)
= P (X > 280.50)
*Use a <em>z</em>-table for the probability.
Thus, the probability that at least 280 of these students are smokers is 0.9664.
Answer:
D(-7,-2)
Step-by-step explanation:
A(-4,3) B(5,-1) C(-2,-6) D(-7,-2)
A: 5×(-4) + 6×3 = -2 ≥ -30 ..... No
B: 2/3×5 + 1 =4.33 ≥ -1 ....No
C: -6 ≤ 2/3×-2 +1 ....No
D: 2/3×(-7)+1 = 2.333 ≤ -2
5×(-7) + 6×(-2) = -47 ≤ -30 ......Yes
