Let's begin by listing out the information given to us:
8 am
airplane #1: x = 80870 ft, v = -450 ft/ min
airplane #2: x = 5000 ft, v = 900ft/min
1.
We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:
2.
We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:
3.
The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:
Answer:
y=28/5
Step-by-step explanation:
Okay so for this we can use cross- multiplication. Basically, the product of the numerator of the first number and the denominator of the second is equal to the product of the denominator of the first and the numerator of the second.
What I mean is: 4*7=5*y
so,
28=5y
y=28/5
Answer:
T = 88 degrees to the nearest degree
Step-by-step explanation:
To find the measure of the angle T, we can use the cosine rule
We have the formula as;
t^2 = u^2 + v^2 - 2uv Cos T
t = 8.1
u = 7.1
v = 4.2
8.1^2 = 7.1^2 + 4.2^2 - 2(7.1)(4.2) cos T
-2.44 = -59.64 cos T
cos T = (2.44)/(59.64)
T = arc cos (2.44/59.64)
T = 87.66
to the nearest degree, this is 88 degrees
Answer: x = 5/4y + 10
y = 4/5x - 8
Step-by-step explanation:
