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2 years ago

14

Evaluate the function. f(x) = -2x2 + 7 Find f(-5)

1 answer:

Alla [95]2 years ago

6 0

-2(-5)^2 + 7
-2 • 5^2 + 7
-2 • 25 + 7
-50 + 7
-43

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Hey uhm can someone answer this for 12 points

MAXImum [283]

$\frac{0.2x - 3.2}{5} = 1.8 \\ 0.2x - 3.2 = 1.8 \times 5 \\ 0.2x - 3.2 = 9 \\ 0.2x = 9 + 3.2 \\ 0.2x = 12.2 \\ x = \frac{12.2}{0.2} \\ \boxed{ x = 61}$

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2 years ago

Read 2 more answers

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

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2 years ago

Solve the system by substitution.<br> 3x-6 = y<br> -6x + y = 9

fomenos

Answer:

https://www.tiger-algebra.com/drill/y=-3x_6;y=9/

Step-by-step explanation:

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3 years ago

Factor the trinomial below.

ivann1987 [24]

Answer: Choice C. (x-7)(x-8)

-------------------------------------------------------

Find two numbers that...
* Multiply to 56 (last term)
* Add to -15 (middle coefficient)

Those two numbers are -7 and -8. So that's why x^2-15x+56 factors to (x-7)(x-8)

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3 years ago

You would like to buy a double burger, a large order of french fries, and a large lemonade, you have $6.44.

jeka94

10$ you need way more

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