Next time, please include the instructions.
This inequality could be broken into two parts:
4m
m + 9 AND m + 9 > -9 + 4m
Focus first on the inequality m + 9 > -9 + 4m. subtract m from both sides, obtaining:
9 > -9 + 3m. Next, add 9 to both sides, obtaining: 18>3m, or m<6
Last step: Determine whether the inequality <span>4m≥m+9 is true if m<6.</span>
The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%
<h3>What is Probability ?</h3>
Probability is defined as the likeliness of an event to happen.
Let X be a random variable that shows the term "freshman 15" that claims that students typically gain 15lb during their freshman year at college.
It is given that
X follows is a normal distribution with a mean of 2.1 lb (μ) and a standard deviation (σ) of 10.8 lb.
Population Mean (μ) = 2.1
Population Standard Deviation (σ) = 10.8
We need to compute Pr(X≥15). The corresponding z-value needed to be computed is:
Then the probability is given as
Pr(X≥15)=0.1162. (11.6%)
The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%
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The answer to this question is A. Simple calculator problem.
Answer:
-10
Step-by-step explanation:
If the equation is 2 x 3+4 x 2-3 x 2- 6(x)= . Than the equation would turn into 2 x 3+4 x 2-3 x 2- 6(3) which equals -10.
