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Citrus2011 [14]
3 years ago
6

What is the final price including tax for the shoes?

Mathematics
1 answer:
Alchen [17]3 years ago
3 0

Answer:

Step-by-step explanation:

$15 × 0.75 × 1.04 = $11.70

$25 × 0.75 × 1.04 = $19.50

$37 × 0.75 × 1.04 = $28.86

$65 × 0.75 × 1.04 = $50.70

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Which of the following is correct?
Natali5045456 [20]
The secomd and third one
7 0
3 years ago
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Please help me with number 53.
zimovet [89]
\dfrac{3\sqrt7+1}{\sqrt5}=\dfrac{(3\sqrt7+1)\cdot\sqrt5}{\sqrt5\cdot\sqrt5}=\dfrac{3\sqrt{35}+\sqrt5}{5}
7 0
4 years ago
A small craft in lake Ontario sends out a distances signal. The coordinates of the boat in trouble are (57,64). One rescue boat
KatRina [158]

Answer:

The coast guard craft will get to the distressed boat the fastest.

Step-by-step explanation:

The coordinates of boat are (57,64).

The coordinates of rescue boat are (67,83).

The  coordinates of coast guard craft are (65,46).

Both rescue crafts travel at the same rate. One of them will get to the distressed boat the faster, whose distance from the boat is least.

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The distance between boat and rescue boat is

d_1=\sqrt{(67-57)^2+(83-64)^2}=21.4709105536\approx 21.47

The distance between boat and coast guard craft is

d_2=\sqrt{(65-57)^2+(46-64)^2}=19.6977156036\approx 19.70

Since the distance between boat and coast guard craft is least, therefore coast guard craft will get to the distressed boat the fastest.

6 0
3 years ago
The following describes a sample. The information given includes the five number summary, the sample size, and the largest and s
lys-0071 [83]

Answer:

L= Q_1 - 1.5*IQR = 210 -1.5*40 =150

U= Q_3 + 1.5*IQR = 250 +1.5*40 =310

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

Step-by-step explanation:

For this case we have the 5 number summary

(160,210,220,250,270)

So then we have:

minimum = 160 , Q1 = 210, Q2= Median=220, Q3 = 250, Max=270

If we find the interquartile range we got:

IQR = Q_3 -Q_1 = 250-210 =40

For this case we need to find the lower and upper limit with the following formulas:

L= Q_1 - 1.5*IQR = 210 -1.5*40 =150

U= Q_3 + 1.5*IQR = 250 +1.5*40 =310

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

4 0
4 years ago
What is the result of −18⋅16 2/3? Enter the result as an improper fraction and as a mixed number.
dlinn [17]
Let's firstly convert the mixed fraction to "improper" and then proceed,

\bf \stackrel{mixed}{16\frac{2}{3}}\implies \cfrac{16\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{50}{3}}\\\\&#10;-------------------------------\\\\&#10;-18\cdot \cfrac{50}{3}\implies \cfrac{-18\cdot 50}{3}\implies \cfrac{-18}{3}\cdot 50\implies -6\cdot 50\implies -300&#10;\\\\\\&#10;\cfrac{-300}{1}\implies -300\frac{1}{1}
8 0
3 years ago
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