<span>2.31*10-^3 using scientific notation
= 0.00231</span>
Answer:
45 square meters
Step-by-step explanation:
we know that
The area of trapezoid is equal to
where
b1 and b2 are the parallel bases
h is the height of trapezoid (perpendicular distance between the parallel bases)
we have
substitute
The number of children who have dogs is ten times more than the number of children who have a rabbit.
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
Answer:
-16
Step-by-step explanation:
k = 3
-2(3) + 5 = -1
k = 4
-2(4) + 5 = -3
k = 5
-2(5) + 5 = -5
k = 6
-2(6) + 5 = -7
(-1) + (-3) + (-5) + (-7)
= -16
