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Tresset [83]
2 years ago
14

Find the values of x for which the denominator is equal to zero for 2x^2+5/x^2-2x .

Mathematics
2 answers:
Elodia [21]2 years ago
3 0

Let's see

\\ \rm\rightarrowtail x^2-2x=0

\\ \rm\rightarrowtail x(x-2)=0

\\ \rm\rightarrowtail x=0\:or\:x-2=0

\\ \rm\rightarrowtail x=0\:or\:x=2

alekssr [168]2 years ago
3 0
<h2>꧁⫷ᴀɴsᴡᴇʀ⫸꧂ </h2><h2 /><h2 />

\green{••••••••••••••••••••••} \blue{••••••••••••••••••••••••••}

\sf {x^2 - 2x = 0}

\sf {x ( x - 2) = 0}

\sf {x = 0 \: or \: x-2 = 0}

\sf \green{ {x = 0 \: or \: x = 2}}

#CarryOnLearning

#LibreAngMatuto

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Your answer for 9 is wrong. The answer is yes because the largest angle = the largest side.

10. AC because largest angle = largest side

11. Literally the same thing as 9 and 10. Largest angle = largest side
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3 years ago
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8 0
3 years ago
A contractor is in charge of hiring people for a construction project. The number of days it would take to complete the project
sweet-ann [11.9K]

Answer:

\text{Domain of x}=[1,\infty), x \in Z^+

Step-by-step explanation:

Given the function: f(x)=\dfrac{280}{x},$ where:

f(x) =number of days it would take to complete the project

x =number of full-time workers.

\text{When x=0, }f(x)=\dfrac{280}{0}=$Undetermined\\\text{When x=1, }f(x)=\dfrac{280}{1}=$280 days\\\text{When x=280, }f(x)=\dfrac{280}{280}=$1 day\\\text{When x=560, }f(x)=\dfrac{280}{560}=$0.5 days

The domain of a function is the complete set of possible values of the independent variable.

In this case, the independent variable is x, the number of full-time workers. We have shown that x cannot be zero as there must be at least a worker on ground.

Therefore, an appropriate domain of the function f(x) is the set of positive integers (from 1 to infinity).

\text{Domain of x}=[1,\infty), x \in Z^+

7 0
3 years ago
A parabola has its vertex at (-6, 5) and focus at (-6.25, 5). Which of the following is an equation for this parabola?
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Answer:

Step-by-step explanation:

vertex and focus are horizontally aligned, so parabola is horizontal.

focal length p = distance between focus and vertex = 0.25

focus lies to the left of vertex, so the parabola opens to the left.

x = a(y-k)² + h,

vertex (h,k)

a = -1/(4p)

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h = -6

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6 0
3 years ago
What is the value of X?
Citrus2011 [14]
(X+12) + 140 = 180

X + 12 + 140 = 180

X + 152 = 180

X = 180 - 152

X = 28
4 0
2 years ago
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