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Tresset [83]
2 years ago
14

Find the values of x for which the denominator is equal to zero for 2x^2+5/x^2-2x .

Mathematics
2 answers:
Elodia [21]2 years ago
3 0

Let's see

\\ \rm\rightarrowtail x^2-2x=0

\\ \rm\rightarrowtail x(x-2)=0

\\ \rm\rightarrowtail x=0\:or\:x-2=0

\\ \rm\rightarrowtail x=0\:or\:x=2

alekssr [168]2 years ago
3 0
<h2>꧁⫷ᴀɴsᴡᴇʀ⫸꧂ </h2><h2 /><h2 />

\green{••••••••••••••••••••••} \blue{••••••••••••••••••••••••••}

\sf {x^2 - 2x = 0}

\sf {x ( x - 2) = 0}

\sf {x = 0 \: or \: x-2 = 0}

\sf \green{ {x = 0 \: or \: x = 2}}

#CarryOnLearning

#LibreAngMatuto

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6x-2y=24<br> how do u solve for y
Tatiana [17]
It's <span>Diophantine equation. 
First, we need to found gcd(6,(-2)):</span>
6=2*3
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So, gcd(6,-2)=2
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8 0
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Procedure for this problem -8+(-24)
lana66690 [7]

Answer: - 32

Step-by-step explanation:

-8 + (-24)

Infront of the Positive is a one.

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6 0
3 years ago
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</span>
Therefore, the best and most correct answer among the choices provided by the question is the fourth choice "<span>15 - 2x ≥ 4y". </span>I hope my answer has come to your help. God bless and have a nice day ahead!
5 0
3 years ago
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