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Tresset [83]
1 year ago
14

Find the values of x for which the denominator is equal to zero for 2x^2+5/x^2-2x .

Mathematics
2 answers:
Elodia [21]1 year ago
3 0

Let's see

\\ \rm\rightarrowtail x^2-2x=0

\\ \rm\rightarrowtail x(x-2)=0

\\ \rm\rightarrowtail x=0\:or\:x-2=0

\\ \rm\rightarrowtail x=0\:or\:x=2

alekssr [168]1 year ago
3 0
<h2>꧁⫷ᴀɴsᴡᴇʀ⫸꧂ </h2><h2 /><h2 />

\green{••••••••••••••••••••••} \blue{••••••••••••••••••••••••••}

\sf {x^2 - 2x = 0}

\sf {x ( x - 2) = 0}

\sf {x = 0 \: or \: x-2 = 0}

\sf \green{ {x = 0 \: or \: x = 2}}

#CarryOnLearning

#LibreAngMatuto

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The circumference of super eight is four times the conference at Circle B which statement about the areas of the circle is true
ICE Princess25 [194]
When you have factors in shapes you must remember:
circumference and perimeter are in one unit measures
area is in squared units
volume is in cubed units

So, when the circumference of A is 4 times that of C there is a factor of 4.
Since we need to know the area the factor 4 will change to a factor of 4² since area is a squared unit.

The solution is 4²=16, the are of circle A is sixteen times the area of circle B.
4 0
2 years ago
Please help me answer this!!!!​
garik1379 [7]
<h3><u>Answer</u><u>:</u></h3>

7 \frac{1}{2}

<h3><u>Explan</u><u>ation</u><u>:</u></h3>

First, convert any mixed numbers to fractions. An easy way to convert:

4 \frac{1}{2}  = 4 \times 2 + 1

<h3>=</h3>

\frac{9}{2}  \div  \frac{3}{5}

Then, apply the fractions formula for division.

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Then, simplify.

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5 0
2 years ago
What is the product of the two integer values for $x$ for which $|x^2 - 16|$ is a prime number?
Nana76 [90]

Answer:

-9

Step-by-step explanation:

x² -16 = (x -4)(x +4)

This magnitude of this product can only be prime if one of the factors is ±1. Any other integer value of x will produce a composite number (or zero).

... For x-4 = ±1, x = 3 or 5

... For x+4 = ±1, x = -3 or -5

The values of x that are ±3 both give |x²-16| = 7, a prime.

The values of x that are ±5 both give |x²-16| = 9, not a prime.

The two values of x that are of interest are x=-3 and x=3. Their product is ...

... (-3)·(3) = -9

8 0
3 years ago
Х-y=5<br> x-2y=3<br><br> Can someone help me
tatiyna
First multiply -1 on the top to cancel X

It will give u:

-X+Y=-5
X-2Y=3 which gives u

y=2

Now, plug in the y (one of the equation it doesn’t matter which one) to solve for X

X-2=5
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7 0
2 years ago
Combine the like terms to create an equivalent expression: r + (−5r)
Harrizon [31]

Answer:

-4r

Step-by-step explanation:

r+(-5r)=r-5r=-4r

6 0
3 years ago
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