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lora16 [44]
2 years ago
14

Find the slope of the line going through the points (-10, 0) and (4, 0). Enter your answer in simplest form. (For example, slope

= -4/2 = -2 )
Mathematics
1 answer:
Kitty [74]2 years ago
6 0

Answer:

y = 0

Step-by-step explanation:

To find the slope, we have to plug the values into the slope-intercept formula.

y2 - y1 / x2 - x1

0 - 0 / 4 - (-10)

0 / 14

= 0

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Consider the line 5x-8y=8 what is the slope of a line perpendicular to this line what is the slope of a line parallel to this li
Sophie [7]

\text{Let}\ k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2,\ \text{then}\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\\text{Convert the equation to the slope-intercept form}\ y=mx+b.\\\\5x-8y=8\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\-8y=-5x+8\qquad\text{divide both sides by (-8)}\\\\y=\dfrac{5}{8}x-1\to m_1=\dfrac{5}{8}\\\\perpendicular:\ m_2=-\dfrac{1}{\frac{5}{8}}=-\dfrac{8}{5}\\\\parallel:\ m_2=\dfrac{5}{8}

8 0
3 years ago
What is the measure of ab?
Paul [167]
I hope this helps you



Where's the question?
4 0
3 years ago
Hai.............point​
Ymorist [56]

Answer:

thanks

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
3 ice cream cones cost $8.25. At this rate , how much do 2 ice cream cones cost?
myrzilka [38]

Answer:

5.5

Step-by-step explanation:

8.25/3=2.75

2.75 times 2 is 5.5

4 0
2 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
Read 2 more answers
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