Answer:
A. (-7 -2)
Step-by-step explanation:
You can eliminate y by multiplying the first equation by 7 and subtracting 6 times the second equation:
7(-3x +6y) -6(5x +7y) = 7(9) -6(-49)
-21x +42y -30x -42y = 63 +294 . . . . eliminate parentheses
-51x = 357 . . . . . . . . collect terms
x = -7 . . . . . . . divide by -51. This matches answer choice A.
(1) For the parabola on the bottom row, the domain would be R and the range would be y ≥ -5
(2) For the hyperbola on the bottom row, the domain would be R\{3} (since there is an asymptote at x = 3) and the range would be R\{4} (since there is an asymptote at y = 4)
(3) For the square root function on the bottom row, the domain would be x ≥ -5 and the range would be (-∞, -2]
(4) For the function to the very right on the bottom row, the domain would be R and the range would be (-∞, -3]
Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
Graph D
Step-by-step explanation:
it does not pass the linear test to qualify as a function
A line in the horizon meaning a straigh flat line, its counterpart is a vertical line which is up and down. If you look at an x/y line, the x line is the horizon line
