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3 years ago

Question 4 of 20

Physics

2 answers:

Semmy [17]3 years ago

7 0

Answer:

c.160 g ball that is rolling north across a field at 2.0 m/s

Explanation:

here the mass and the velocity matters

lesser the mass and velocity, lesser the momentum

I hope this can help you . unlock a badge and mark me as brainliest

Nookie1986 [14]3 years ago

5 0

Answer:

Which ball has the least momentum? C. A 160 g ball that is rolling north across a field at 2.0 m/s

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A 61 kg skier leaves the end of a ski-jump ramp with a velocity of 27 m/s directed 21° above the horizontal. Suppose that as a r

Harman [31]

Answer:

22kj

Explanation:

set h = 0 at the end of slide.

final height is -12m

initial condition will be Ui = 0

Ki = 1/2mv² = 1/2 x 61 x (27)² = 22234.5J

Final condition is Ui = mgh = 61 x 9.8 x -12 = -7173J

Ki = 1/2mv²

Ki= 1/2 x 61 x (16)² = 7808J

conservation energy says that

Ui + Ki = Uf +Kf +ΔEth

so ΔEth = Ui + Ki - Uf - Kf

ΔEth = 22234.5 - 7808 + 7173

ΔEth = 21600J

ΔEth =22Kj

7 0

3 years ago

Read 2 more answers

Mr. Smith challenged his students to create an electromagnet that will pick up more paper clips than anyone else in the class. T

aliya0001 [1]

Wrap the wire very tight around the iron nail.

5 0

3 years ago

Read 2 more answers

1. A 1000 kg bag of sand has an<br> acceleration of 0.5m/s/s. What is the<br> force on the bag?

densk [106]

Answer:

We conclude that the force on the bag is 500 N.

Explanation:

Given

Mass m = 1000 kg

Acceleration a = 0.5 m/s²

To determine

Force F = ?

We know that when a force is applied to a body, it produces acceleration.

<u>Important Tip: </u>

We can determine the force on the bag using the formula F = ma

Using the formula

$F = ma$

where

$F$ is the force

$m$ is the mass

$a$ is the acceleration

now substitute m = 1000, and a = 0.5 m/s² in the formula

$F = ma$

$F = (1000)(0.5)$

$F=500$ N

Therefore, we conclude that the force on the bag is 500 N.

5 0

3 years ago

A tumbleweed is moving with a velocity of 5.4 m/s westward. A sudden gust of wind blows for 1.5 seconds and reduces its velocity

Klio2033 [76]

Answer:

$a=-2.4 m/s^{2}$

Explanation:

Let's recall the acceleration definition.

$a=\frac{\Delta v}{\Delta t}$ (1)

Δv is the velocity variation, Δv = v(f) - v(i). It is just the difference between final and initial velocities. So Δv = 1.8[m/s] - 5.4[m/s] = -3.6 [m/s]

And Δt is the time variation, in this case it is just 1.5 s.

Therefore, using the equation (1), the acceleration will be:

$a=\frac{-3.6}{1.5}=-2.4 m/s^{2}$

The minus sign means that the tumbleweed is slowing down.

I hope it helps you!

8 0

3 years ago

starting from rest, a car accelerates at a rate of 10.7 m/s^2 for 12 seconds. what is its velocity at the end of this time?

kherson [118]

Velocity of the car at the end of this time=128.4 m/s

Explanation:

initial velocity Vi=0

final velocity=V

acceleration= a=10.7 m/s²

time =t=12 s

using kinematic equation V= Vi + at

V=0+ 10.7 (12)

V=128.4 m/s

Thus the final velocity of the car =128.4 m/s

8 0

3 years ago