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2 years ago

Express each decimal as a fraction in simplest form. help-

Mathematics

1 answer:

SVETLANKA909090 [29]2 years ago

4 0

Answer:

1. 1/2

2. 4/5

3. 9/10

4. 3/4

5. 12/25

6. 18/25

Step-by-step explanation:

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Charlier is cutting a 10 3/8 foot piece of wood to make shelves for his bedroom. Does Charlie have enough wood to make four shel

Misha Larkins [42]

2 5/8 × 4 = 10 1/2

Charlie does not have enough wood because 10 1/2 is also equal to 10 4/8 and Charlie only has 10 3/8

hope this helped

7 0

3 years ago

Two numbers, x and y, are related as described in this statement: x to the power of 3 is equal to y to the power of 5. Which equ

Aleonysh [2.5K]

The mathematical sentence can be written as:

x^3 = y^5

<h3>How to write the expression?</h3>

A number a to the power of n is written as:

a^n

Then:

"x to the power of 3 is equal to y to the power of 5"

Would be written as:

x^3 = y^5

Particularly, this does not appear in the given options, but this is the correct and simplest way of writing the given mathematical sentence.

If you want to learn more about expressions, you can read:

brainly.com/question/4344214

4 0

2 years ago

A water company charges a connection fee each month of $22 and an additional $2.30 per cubic foot of water used. Which function

EastWind [94]

Answer

Find out the total monthly charges for x cubic feet of water used .

To prove

As given

A water company charges a connection fee each month of $22 and an additional $2.30 per cubic foot of water used.

Than the equation become

Total monthly charges for x cubic feet of water used = Monthly connection fee + charges for x cubic feet of water

thus

f(x) = 22 + 2.30x

where x is the x cubic feet of water used .

Therefore Option (B) is correct i.e f(x) = 22 + 2.30x .

4 0

2 years ago

Read 2 more answers

Evaluate the line integral by the two following methods. xy dx + x2 dy C is counterclockwise around the rectangle with vertices

Airida [17]

Answer:

25/2

Step-by-step explanation:

Recall that for a parametrized differentiable curve C = (x(t), y(t)) with the parameter t varying on some interval [a, b]

$\large \displaystyle\int_{C}[P(x,y)dx+Q(x,y)dy]=\displaystyle\int_{a}^{b}[P(x(t),y(t))x'(t)+Q(x(t),y(t))y'(t)]dt$

Where P, Q are scalar functions

We want to compute

$\large \displaystyle\int_{C}P(x,y)dx+Q(x,y)dy=\displaystyle\int_{C}xydx+x^2dy$

Where C is the rectangle with vertices (0, 0), (5, 0), (5, 1), (0, 1) going counterclockwise.

a) Directly

Let us break down C into 4 paths $\large C_1,C_2,C_3,C_4$ which represents the sides of the rectangle.

$\large C_1$ is the line segment from (0,0) to (5,0)

$\large C_2$ is the line segment from (5,0) to (5,1)

$\large C_3$ is the line segment from (5,1) to (0,1)

$\large C_4$ is the line segment from (0,1) to (0,0)

Then

$\large \displaystyle\int_{C}=\displaystyle\int_{C_1}+\displaystyle\int_{C_2}+\displaystyle\int_{C_3}+\displaystyle\int_{C_4}$

Given 2 points P, Q we can always parametrize the line segment from P to Q with

r(t) = tQ + (1-t)P for 0≤ t≤ 1

Let us compute the first integral. We parametrize $\large C_1$ as

r(t) = t(5,0)+(1-t)(0,0) = (5t, 0) for 0≤ t≤ 1 and

r'(t) = (5,0) so

$\large \displaystyle\int_{C_1}xydx+x^2dy=0$

Now the second integral. We parametrize $\large C_2$ as

r(t) = t(5,1)+(1-t)(5,0) = (5 , t) for 0≤ t≤ 1 and

r'(t) = (0,1) so

$\large \displaystyle\int_{C_2}xydx+x^2dy=\displaystyle\int_{0}^{1}25dt=25$

The third integral. We parametrize $\large C_3$ as

r(t) = t(0,1)+(1-t)(5,1) = (5-5t, 1) for 0≤ t≤ 1 and

r'(t) = (-5,0) so

$\large \displaystyle\int_{C_3}xydx+x^2dy=\displaystyle\int_{0}^{1}(5-5t)(-5)dt=-25\displaystyle\int_{0}^{1}dt+25\displaystyle\int_{0}^{1}tdt=\\\\=-25+25/2=-25/2$

The fourth integral. We parametrize $\large C_4$ as

r(t) = t(0,0)+(1-t)(0,1) = (0, 1-t) for 0≤ t≤ 1 and

r'(t) = (0,-1) so

$\large \displaystyle\int_{C_4}xydx+x^2dy=0$

$\large \displaystyle\int_{C}xydx+x^2dy=25-25/2=25/2$

Now, let us compute the value using Green's theorem.

According with this theorem

$\large \displaystyle\int_{C}Pdx+Qdy=\displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx$

where A is the interior of the rectangle.

so A={(x,y) | 0≤ x≤ 5, 0≤ y≤ 1}

We have

$\large \displaystyle\frac{\partial Q}{\partial x}=2x\\\\\displaystyle\frac{\partial P}{\partial y}=x$

$\large \displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx=\displaystyle\int_{0}^{5}\displaystyle\int_{0}^{1}xdydx=\displaystyle\int_{0}^{5}xdx\displaystyle\int_{0}^{1}dy=25/2$

3 0

3 years ago

Two-thirds a number plus 4 is 7

faltersainse [42]

2/3n (put that as a fraction) + 4 = 7

6 0

3 years ago