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Dafna1 [17]
3 years ago
5

Light travels through space at a speed of 299,792,458 m/s. how fast is that in miles per minute

Physics
1 answer:
Bezzdna [24]3 years ago
4 0

Answer:

11 176 943.8 miles per minute

Explanation:

according to a reliable source

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A force of 6 N is used to open a door, wherein the distance of the force to the axis of rotation is 80 cm. If the angular accele
Luda [366]

Explanation:

∑τ = Iα

(6 N) (0.80 m) = I (0.5 rad/s²)

I = 9.6 kg m²

7 0
4 years ago
Gina applied 1,780 J of work to move a sofa 3.8 meters. What amount of force did she exert?
Gnoma [55]

Answer:

468.42N

Explanation:

Here,

Work done(W)=1780J

Displacement(s)=3.8m

As we have,

Work=Force×displacement

Now,

\hookrightarrow 1780J=F\times3.8m\\\\\hookrightarrow \frac{1780J}{3.8m} =F\\\\\hookrightarrow F=468.42N

7 0
2 years ago
A horizontal spring has spring constant k = 360 N/m. First, compress the spring from its uncompressed length (x = 0) to x = 11.0
mixas84 [53]

Here we can say that by energy conservation principle

Elastic potential energy of spring will convert into kinetic energy of the block

so here we will have

\frac{1}{2} kx^2 = \frac{1}{2}mv^2

we also know that

k = 360 N/m

x = 11 cm

m = 1.85 kg

now we will use all in above equation

\frac{1}{2}\times 360\times (0.11)^2 = \frac{1}{2}\times (1.85) v^2

4.356 = 0.925 v^2

v^2 = 4.71

v = 2.17 m/s

so it will move with speed 2.17 m/s after separating from spring

7 0
3 years ago
Read 2 more answers
Why do baseball pitchers throw the ball at an angle that is slightly above the horizontal if they want the ball to reach at appr
lesantik [10]

Answer:

The angle above the horizontal at which the pitcher throws the ball determines the distance the ball travels before returning to the height at which it was thrown

Explanation:

The baseball is thrown as a projectile and the range, 'R', of the baseball which is the distance the baseball travels before the height above the ground returns to the initial height  is given given as follows;

R = \dfrac{u^2 \cdot sin(2\cdot \theta )}{g}

Where;

R = The range of the baseball = The horizontal distance away from the pitcher the ball reaches

u = The initial velocity with which the baseball was thrown

θ = The angle above horizontal a baseball pitcher throws the ball

g = The acceleration due to gravity ≈ 9.81 m/s²

From the the equation, when θ = 0, sin(θ) = sin(0) = 0 and the ball does not cover any horizontal distance before going lower than the height at which it was thrown, therefore, for the ball to travel further, the angle of launch, θ has to be larger than 0.

4 0
3 years ago
I need help with number 3,
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