Answer
given,
change in enthalpy = 51 kJ/mole
change in activation energy = 109 kJ/mole
when a reaction is catalysed change in enthalpy between the product and the reactant does not change it remain constant.
where as activation energy of the product and the reactant decreases.
example:
ΔH = 51 kJ/mole
E_a= 83 kJ/mole
here activation energy decrease whereas change in enthalpy remains same.
Kinetic energy= .5 x m x v^2
KE=.5 x 4.2 x 3.85^2
KE=31.13
I believe that B is the answer.
Answer:
28.7%
Explanation:
efficiency = work output /work input × 100
