Answer:
The total surface area of this square pyramid is 
Step-by-step explanation:
we know that
The surface area of a square pyramid is equal to
![SA=b^{2} +4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have
----> the length side of the square base
----> the height of the triangular faces
substitute the values
![SA=9^{2} +4[\frac{1}{2}(9)(12)]=297\ mm^{2}](https://tex.z-dn.net/?f=SA%3D9%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%289%29%2812%29%5D%3D297%5C%20mm%5E%7B2%7D)
Answer:
1. C 2.D 3.D 4.A
Step-by-step explanation:
The first one would be C because the slope is -1, which can also be -x and the y-intercept is 0, meaning you don't need to add or subtract anything.
The second one is D because the slope is -3, meaning it's -3x, and the y-intercept is positive, meaning you add 5.
The third one is D because the slope is 5/4, which is 5/4x and the y-intercept is positive 3, meaning you add 3.
And the fourth one is A because there is no slope, so y would just equal 3.
2 - 12 + 18
= -10 + 18
= 8
The answer is D.
C. Is try correct answer
See example in the attached picture
