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2 years ago

Please help i will give extra points

Mathematics

1 answer:

klemol [59]2 years ago

5 0

Answer:

$36 \div (3 \times 2) - 4 \\ 36 \div 6 - 4 \\ 6 - 4 \\ = 2$

<h3><u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u></h3>

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Which is greater 4 ft 7 inches or 56 inches

jok3333 [9.3K]

1 ft = 12 in.
4 ft = 4 * 1 ft = 4 * 12 in. = 48 in.

4 ft 7 in. = 48 in. + 7 in. = 55 in.

4 ft 7 in. < 56 in.

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3 years ago

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Which is the opposite side to the reference angle C?*

geniusboy [140]

Answer:

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Explanation:

The opposite side is the side that is not touching the reference angle.

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2 years ago

Margie needs to know the square footage for the first floor of the condo her client wants to make an offer on. The kitchen is 10

irga5000 [103]

Answer:

D. 850 square foot

Step-by-step explanation:

Area of a space is the length

multiply by the width

The area for the kitchen, dining, office and sunroom will be calculated independently and added together.

Note the word "and the office and sunroom are each 10 feet by 10 feet"

Kitchen area = 10 ft x 15ft= 150sqft

Living/Dining area = 20ftx25ft= 500sqft

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Office= 10ftx10ft=100sqft

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3 years ago

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On weekends a movie ticket costs $10.50. form an inequality and solve it to find the maximum number of tickets kate can buy with

Greeley [361]

$10.50

10 Tickets would be $105.00

$105.00 - $10.50 = $94.50 so 9 Tickets would be $94.50

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2 years ago

A survey of athletes at a high school is conducted, and the following facts are discovered: 13% of the athletes are football pla

nekit [7.7K]

Answer:

The probability that an athlete chosen is either a football player or a basketball player is 56%.

Step-by-step explanation:

Let the athletes which are Football player be 'A'

Let the athletes which are Basket ball player be 'B'

Given:

Football players (A) = 13%

Basketball players (B) = 52%

Both football and basket ball players = 9%

We need to find probability that an athlete chosen is either a football player or a basketball player.

Solution:

The probability that athlete is a football player = $P(A)= \frac{13}{100}=0.13$

The probability that athlete is a basketball player = $P(B)= \frac{52}{100}=0.52$

The probability that athlete is both basket ball player and football player = $P(A\cap B) = \frac{9}{100}=0.09$

We have to find the probability that an athlete chosen is either a football player or a basketball player $P(A\cup B)$ .

Now we know that;

$P(A\cup B)= P(A) + P(B) - P(A \cap B)\\\\P(A\cup B) = 0.13+0.52-0.09=0.56\\\\P(A\cup B) = \frac{0.56}{100}=56\%$

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.

5 0

3 years ago