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crimeas [40]
2 years ago
5

It is easier to determine the electron configurations for the p-block elements in periods 1, 2, and 3 than to determine the elec

tron configurations for the rest of the p-block elements in the periodic table because
they have a larger number of core electrons.
their electrons are assigned to s and p orbitals only.
their electrons are placed in a higher number of orbitals.
they have more valence electrons available for bonding.
Chemistry
1 answer:
babymother [125]2 years ago
5 0

Answer:

Their electrons are placed in a higher number of orbitals

Explanation:

  • Suppose a element be Ga .

The atomic no is 31

The configuration is given by

\\ \sf\longmapsto 1s^22s^22p^63ss^23p^63d^{10}4s^24p^1

Or

\\ \sf\longmapsto [Ar]3d^{10}4s^24p^1

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What compound is this?
Nezavi [6.7K]

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7 0
2 years ago
Keq for the reaction below is 2400. If the initial conditions of the reaction are a 1.0 L flask that contains 0.024 mol NO (g),
podryga [215]

Answer:

The answer to your question is it is not at equilibrium, it will move to the products.

Explanation:

Data

Keq = 2400

Volume = 1 L

moles of NO = 0.024

moles of N₂ = 2

moles of O₂ = 2.6

Process

1.- Determine the concentration of reactants and products

[NO] = 0.024 / 1 = 0.024

[N₂] = 2/1 = 2

[O₂] = 2.6/ 1= 2.6

2.- Balanced chemical reaction

                     N₂ + O₂    ⇒   2NO

3.- Write the equation for the equilibrium of this reaction

                     Keq = [NO]²/[N₂][O₂]

- Substitution

                    Keq = [0.024]² / [2][2.6]

-Simplification

                    Keq = 0.000576 / 5.2

-Result

                    Keq = 1.11 x 10⁻⁴

Conclusion

It is not at equilibrium, it will move to the products because the experimental Keq was lower than the Keq theoretical-

                         1.11 x 10⁻⁴ < 2400

7 0
3 years ago
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