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crimeas [40]
3 years ago
5

It is easier to determine the electron configurations for the p-block elements in periods 1, 2, and 3 than to determine the elec

tron configurations for the rest of the p-block elements in the periodic table because
they have a larger number of core electrons.
their electrons are assigned to s and p orbitals only.
their electrons are placed in a higher number of orbitals.
they have more valence electrons available for bonding.
Chemistry
1 answer:
babymother [125]3 years ago
5 0

Answer:

Their electrons are placed in a higher number of orbitals

Explanation:

  • Suppose a element be Ga .

The atomic no is 31

The configuration is given by

\\ \sf\longmapsto 1s^22s^22p^63ss^23p^63d^{10}4s^24p^1

Or

\\ \sf\longmapsto [Ar]3d^{10}4s^24p^1

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4 years ago
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(a) Consider the reaction of hydrogen sulfide with methane, given below:
Burka [1]

Answer:

a. H2S(g)/t = 1.48 mol/s

CS2(g)/t = 0.740mol/s

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b. Ptot /t = 981torr/min

Explanation:

a. Based on the reaction:

CH4(g) + 2 H2S(g) → CS2(g) + 4 H2(g)

<em>1 mole of CH4 reacts with 2 moles of H2S producing 1 mole of CS2 and 4 moles of 4H2</em>

<em />

If CH4 decreases at the rate of 0.740mol/s, H2S decreases twice faster, that is 0.740mol/s = 1.48 mol/s

CS2 is produced with the same rate of CH4 because 1 mole of CH4 produce 1 mole of CS2 = 0.740mol/s

The H2 is produced four times faster than CH4 is decreased, that is:

0.740mol/s * 4 = 2.96mol/s

b. With the reaction:

2 NH3(g) → N2(g) + 3 H2(g)

2 moles of ammonia are consumed whereas 1 mole of N2 and 3 moles of H2 are produced.

That means 2 moles of gas are consumed and 4 moles of gas are produced.

If the NH3 decreases at a rate of 327torr/min, the gases are produced in a rate twice faster. That is 327torr/min*2 =

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654torr/min + 327torr/min =

981torr/min

6 0
4 years ago
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2 years ago
How many moles of potassium hydroxide are needed to completely react with 2.94 moles of aluminum
S_A_V [24]

The balanced equation is

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3 years ago
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