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fgiga [73]
3 years ago
9

Why is it important to note the temperature when determining the density of a substance?

Chemistry
1 answer:
Andru [333]3 years ago
7 0
It is important to take note of th temperature in determining the density of a substance because this will set as a basis and will likely be a variable in the experiment because this will also contribute on the effects of the experiment and a basis of how the experiment has turned to be that way.
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Calculate the average atomic mas of an unknown element that has two naturally-occurring isotopes.
professor190 [17]
The average atomic mass if the element above is calculated by the sum of the product of the isotope abundance and its atomic mass unit. It is expressed as:

Average atomic mass = Σ xi(Mi)
<span>Average atomic mass = (.7547 x 248.7) + (.2453 x 249.4) = 248.87
</span>
Hope this helps.
8 0
3 years ago
Read 2 more answers
The useful metal manganese can be extracted from the mineral rhodochrosite by a two-step process. In the first step, manganese(I
ale4655 [162]

Answer:

The answer is "6.52 kg and 13.1 kg"

Explanation:

For point a:  

Actual\ yield = 6.52 \ kg\\\\Percent \ yield= 66\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical\ yield} \times 100 \%\\\\Theoretical\ yield \ of \ MnO_2 = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\=\frac{6.52 \ kg}{66 \%} \times 100\% =9.88 \ kg\\\\

Equation:  

3MnCO_3 +O_2 \longrightarrow 2MnO_2 + 2CO_2\\\\

Calculating the amount of MnCO_3

= 9.88 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ MnO_2}{86.94 \ g} \times \frac{2 \ Mol \ MnCO_3}{2 \ mol \ MnO_2} \times \frac{114.95\ g}{1 \ mol \ MnCO_3 }\times \frac{1\ kg}{1000\ g}\\\\=  13.1 \ kg

For point b:

Actual\ yield = 4.0 \ kg\\\\Percent\ yield=97.0\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical \ yield} \times 100 \% \\\\Theoretical \ yield\  of\  Mn = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\

=\frac{4.0 \ kg}{97.0\%} \times 100\% =4.12 \ kg

Equation:  

3MnO_2 +4AL \longrightarrow 3Mn + 2AL_2O_3\\\\

Calculating the amount of MnO_2:  

= 4.12 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ Mn}{54.94 \ g} \times \frac{3 \ Mol \ MnO_2}{3 \ mol \ Mn} \times \frac{86.94 \ g}{1 \ mol \ MnO_2 }\\\\=  6516 \ g \\\\=6.52 \ kg\\\\

7 0
3 years ago
Each incomplete reaction is a neutralization reaction. Match each equation with the salt formed. 1. H2SO4 + 2NH4OH → ? 2. 2NaOH
sergey [27]

1. H₂SO₄ + 2NH₄OH ⟶ (NH₄)₂SO₄ + 2H₂O


2. 2NaOH + H₂CO₃ ⟶ Na₂CO₃ + 2H₂O


3. HNO₃ + KOH ⟶ KNO₃ + H₂O


<em>Explanation</em>:

Acid + base ⟶ salt + water


Take the H from the acid and the OH from the base to get water.


Then, join what’s left to get the salt. Write the symbol for the metal first.


For example, in equation 3, take the H from HNO₃ and the OH from KOH.


Combining the remaining parts (NO₃ and K) to get the salt, KNO₃.


7 0
3 years ago
Read 2 more answers
Liquids that do not mix are called
djyliett [7]

Answer:

Immiscible liquids

Explanation:

Immiscible comes from two words; 'im' indicating a negation or a contradiction; and 'miscere' meaning to mix.

Putting the words together, immiscible means not able to mix.

3 0
3 years ago
How many molecules of O2 are in 153.9 g O2?
MrRissso [65]

Answer:

2.895*10^24

Explanation:

mass of Oxygen give = 153.9g

molar mass of O2 molecule = 16*2=32g/mol

n= mole

To find the mole

n= mass/ molar mass

n= 153.9/32

n=4.81mol.

To find the number of molecules of o

Nm= number of molecule

Nn = Number of mole

NA = number of Avogados

Nm= Nn * NA

Nm= 4.81 *6.02*10^23

Nm= 2.895*10^24

3 0
2 years ago
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