Which of the following situations is most favorable for solubility? View Available Hint(s) Which of the following situations is
2 answers:
Answer: Option (a) is the correct answer.
Explanation:
It is known that more is the attraction between molecules of a solute with the solvent molecules then more attraction takes place. Due to this more number of solute particles will dissolve in the solvent.
For example, NaCl is an ionic compound and water is a polar solvent. So, when we dissolve NaCl (solute) in water (solvent) then sodium chloride will completely dissolve in water because like dissolves like.
This also means that due to the strong attraction between NaCl molecules and water molecules the salt dissociates into and
ions.
Thus, we can conclude that out of the given options strong attraction between solute particles situation is most favorable for solubility.
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Answer:
(a)
(b)
(c)
(d)
(e)
Explanation:
To calculate de pH of an acid solution the formula is:
were [H^{+}] is the concentration of protons of the solution. Therefore it is necessary to know the concentration of the protons for every solution in order to solve the problem.
(a) and (c) are strong acids so they dissociate completely in aqueous solution. Thus, the concentration of the acid is the same as the protons.
(b) and (e) are strong bases so they dissociate completely in aqueous solution too. Thus, the concentration of the base is the same as the oxydriles. But in this case it is necessary to consider the water autoionization to calculate the protons concentration:
clearing the
(d) is a weak base so it is necessary to solve the equilibrium first, knowing
The reaction is →
so the equilibrium is
clearing the <em>x</em>