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Kay [80]
2 years ago
6

Which of the following situations is most favorable for solubility? View Available Hint(s) Which of the following situations is

most favorable for solubility? strong attraction between solute particles strong attraction between solvent particles strong attraction of solute particles to solvent particles Submit
Chemistry
2 answers:
bixtya [17]2 years ago
7 0

Answer:

strong attraction of solute particles to solvent particles

Explanation:

Solubility occurs when the solute-solvent attraction is more than the solute-solute and solvent-solvent interactions.

<u>A solute solubles in the solvent when the solute solute interactions and the solvent solvent interaction decreases and there is more strong interaction of the solute particles to the solvent particles. </u>

iogann1982 [59]2 years ago
7 0

Answer: Option (a) is the correct answer.

Explanation:

It is known that more is the attraction between molecules of a solute with the solvent molecules then more attraction takes place. Due to this more number of solute particles will dissolve in the solvent.

For example, NaCl is an ionic compound and water is a polar solvent. So, when we dissolve NaCl (solute) in water (solvent) then sodium chloride will completely dissolve in water because like dissolves like.

This also means that due to the strong attraction between NaCl molecules and water molecules the salt dissociates into Na^{+} and Cl^{-} ions.

Thus, we can conclude that out of the given options strong attraction between solute particles situation is most favorable for solubility.

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According to the principle of the conservation of mass the mass of the sodium sulfate was the following PLS HELP I NEED TO TURN
Annette [7]

Answer:

Explanation:

The Law of Conservation of Mass is defined and explained using examples of reacting mass calculations using the law are fully explained with worked out examples using the balanced symbol equation. The method involves reacting masses deduced from the balanced symbol equation.

5 0
2 years ago
What all indicates a CHEMICAL change? *
myrzilka [38]

one substance becomes two new substances

6 0
3 years ago
Consider the reaction 3X + 2Y 5C + 4D
xeze [42]

Answer:

This problem is providing a chemical equation between two hypothetical elements, X and Y and asks for the molesof X that are needed to 

produce 21.00 moles of D in excess Y. After the following work, the answer turns out to be 15.75 mol X:Mole ratios:In chemistry, one the most crucial branches is stoichiometry, which allows us to perform calculations with grams, moles and particles (atoms, molecules and ions). It is based on the concept of mole ratios, whereby the moles of a specific substance can be converted to moles of another one, say product to reactant, reactant to reactant, reactant to product and product to product.

Calculations:In such a way, since 21.00 moles of D are given, we need the mole ratio of D to X in order to get the answer, which according to the reaction is 3:4 based on their coefficients in the reaction. Hence, we calculate the required as follows:

Explanation:

mark me brainliest!!

5 0
2 years ago
The great French chemist Antoine Lavoisier discovered the Law of Conservation of Mass in part by doing a famous experiment in 17
yawa3891 [41]

Answer:

a. 2 HgO(s) ⇒ 2 Hg(l) + O₂(g)

b. 0.957 g

Explanation:

Step 1: Write the balanced equation

2 HgO(s) ⇒ 2 Hg(l) + O₂(g)

Step 2: Convert 130.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15

K = 130.0°C + 273.15

K = 403.2 K

Step 3: Calculate the moles of O₂

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 1 atm × 0.0730 L/0.0821 atm.L/mol.K × 403.2 K

n = 2.21 × 10⁻³ mol

Step 4: Calculate the moles of HgO that produced 2.21 × 10⁻³ moles of O₂

The molar ratio of HgO to O₂ is 2:1. The moles of HgO required are 2/1 × 2.21 × 10⁻³ mol = 4.42 × 10⁻³ mol.

Step 5: Calculate the mass corresponding to 4.42 × 10⁻³ moles of HgO

The molar mass of HgO is 216.59 g/mol.

4.42 × 10⁻³ mol × 216.59 g/mol = 0.957 g

5 0
3 years ago
Which formula can be used to calculate the theoretical yield?
Bas_tet [7]

Answer:

Option C, (Actual yield ÷ percent yield) × 100

Explanation:

Theoretical yield is defined as the total amount of product formed for given reactants in a chemical reaction.  It is an ideal case which assumes no exceptions or wastage.

The mathematical relation between the actual yield, percent yield and theoretical yield is as follows -

P.Y. = \frac{M_{A.Y.}}{M_{T.Y.}} * 100

Where

P.Y. represents the percent yield a

M A.Y. represents the mass obtained from actual yield

M T.Y. represents the mass obtained from theoretical yield

Hence, if we rearrange the formula, we get -

M_{T.Y.} = \frac{M_{A.Y.}}{P.Y.} * 100

Hence, option C is correct

5 0
2 years ago
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