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3 years ago

A car starts from rest and accelerates at 5 m/s/s.

Physics

1 answer:

goldenfox [79]3 years ago

3 0

Please find attached photograph for your answer. Hope it helps. Please do comment

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To understand black body radiation, physicists should view light as having what type of properties

FinnZ [79.3K]

Properties of a particle answer D

7 0

3 years ago

Read 2 more answers

A 1200-kg car moving at 15.6 m/s suddenly collides with a stationary car of mass 1500 kg. if the two vehicles lock together, wha

g100num [7]

Use conservation of momentum ;

m1u1 + m2u2 = m1v1 + m2v2

1200×15.6 + 0 = 2700v

v = 18720/2700

v = 6.933 or ~ 7 m/s

5 0

3 years ago

Pluto’s diameter is approximately 2370 km, and the diameter of its satellite Charon is 1250 km. Although the distance varies, th

MissTica

Answer:

$r_{cm} = 2520.5 km$

Explanation:

As we know that mass is the product of volume and density

so we will have

$M = \rho V$

here we have

$M = \rho(\frac{4}{3}\pi r^3)$

so we will have

$\frac{M_p}{M_c} = (\frac{r_p}{r_c})^3$

so we will have

$\frac{M_p}{M_c} = (\frac{2370}{1250})^3$

$M_p = 6.81 M_c$

now let the position of Pluto is at origin so we have

$r_{cm} = \frac{M_p (0) + M_c(19700)}{M_p + M_c}$

$r_{cm} = \frac{19700}{\frac{M_p}{M_c} + 1}$

$r_{cm} = \frac{19700}{6.81 + 1}$

$r_{cm} = 2520.5 km$

5 0

3 years ago

You step onto a hot beach with your bare feet. A generated in your foot, travels through your nervous system at an average speed

madreJ [45]

Answer: 12.44 millisecond

Explanation:

Based on the information given, to know the time taken for the impulse, which travels a distance of 1.58m to reach the brain will be:

Time taken = Distance/Speed

Time taken = 1.58/127

Time taken = 0.01244

Time taken = 12.44 millisecond.

7 0

3 years ago

A real image is four times as far from a lens as is theobject.

saveliy_v [14]

Answer:

1.25 focal lengths

Explanation:

The lens equation states that:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where

f is the focal length

p is the object distance

q is the image distance

In this problem, the image is 4 times as far from the lens as is the object: this means that

$q=4p$

If we substitute this into the lens equation and we rearrange it, we get

$\frac{1}{f}=\frac{1}{p}+\frac{1}{4p}=\frac{4+1}{4p}=\frac{5}{4p}\\p=\frac{5}{4}f=1.25 f$

so, the object distance measured in focal lengths is

1.25 focal lenghts

3 0

3 years ago