Answer:
90-100meters
Explanation:
The overall length limitation of a UTP cable is 90-100meters. Once this limitation is reached, a repeater is employed to transfer data.
Answer:
75.5g
Explanation:
From the ionic equation, we can write

next we find the number of charge
Note Q=it
for i=8.5A, t=3.75 to secs 3.75*60*60=13500secs
hence

Since one faraday represent one mole of electron which equal 96500C
Hence the number of mole produced by 114750C is
114750/96500=1.2mol
The mass of copper produced is

Hence the amount of copper produced is 75.5g
closed and unsecure circuit
Answer:


Explanation:
<u>Displacement
</u>
It's a vector magnitude that measures the space traveled by a particle between an initial and a final position. The total displacement can be obtained by adding the vectors of each individual displacement. In the case of two displacements:

Given a vector as its polar coordinates (r,\theta), the corresponding rectangular coordinates are computed with


And the vector is expressed as

The monkey first makes a displacement given by (0.198 km,0°). The angle is 0 because it goes to the East, the zero-reference for angles. Thus the first displacement is

The second move is (145 m , -15.8°). The angle is negative because it points South of East. The second displacement is

The total displacement is


In (magnitude,angle) form:



