Answer:
∫ C ( y + e√x) dx + ( 2x + cosy² ) dy = 1/3
Step-by-step explanation: See Annex
Green Theorem establishes:
∫C ( Mdx + Ndy ) = ∫∫R ( δN/dx - δM/dy ) dA
Then
∫ C ( y + e√x) dx + ( 2x + cosy² ) dy
Here
M = 2x + cosy² δM/dy = 1
N = y + e√x δN/dx = 2
δN/dx - δM/dy = 2 - 1 = 1
∫∫(R) dxdy ∫∫ dxdy
Now integration limits ( see Annex)
dy is from x = y² then y = √x to y = x² and for dx
dx is from 0 to 1 then
∫ dy = y | √x ; x² ∫dy = x² - √x
And
∫₀¹ ( x² - √x ) dx = x³/3 - 2/3 √x |₀¹ = 1/3 - 0
∫ C ( y + e√x) dx + ( 2x + cosy² ) dy = 1/3
Answer:
2p-1
Step-by-step explanation:
-4p-(1-6p)
when there is "-" in front of an expression, change the sign of each term of the expression.
-4p -1 + 6p
-4p + 6p =2p
2p -1
Answer:
540.6 mi
Step-by-step explanation:
The angle of depression = angle of elevation = 6°
Let x = the distance to the runway.
tan 6 = 30000/x
xtan 6 = 30000
x = 30000/tan 6 =285430.9 ft
285430.9336.../5280 = 540.6 mi
Answer: I think its 4 + 2m
Answer:
100%
Step-by-step explanation: