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Taya2010 [7]
3 years ago
14

What is the sum for each of these??

Mathematics
1 answer:
Licemer1 [7]3 years ago
5 0

Step-by-step explanation:

\frac{3}{5}  +  \frac{1}{2}  \\   \\  \frac{6 + 5}{10}  \\  \\  \frac{11}{10}

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Consider the function f(x) = {(6)". What is the value of the growth factor of the function?
Firlakuza [10]

Answer:

18

Step-by-step explanation:

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4 years ago
On a scale drawing, a building is 5.5 tall. If the scale if the drawing is 1 inch: 8 ft, how tall is the building
arsen [322]
First, since the building is 5.5 inches and the scale is 1 inch for 8 feet, you would multiply 5.5* 8 to get 44 feet.
7 0
3 years ago
Evaluate each expression for g = -7 and h = 3 and match it to its value.
Molodets [167]

The given expressions are solved and matched

<h3><u>Solution:</u></h3>

To match the given expressions we need to solve the expressions with the given values of g and h and find their value.

Given that g = -7 and h = 3

\begin{array}{l}{\text { 1) } g+h=-7+3=-4} \\\\ {\text { 2) } g-h=-7-3=-10} \\\\ {\text { 3) } h-g=3+7=10} \\\\ {\text { 4) } g h=-7 \times 3=-21} \\\\ {\text { 5) } g+h^{2}=-7+3^{2}=-7+9=2} \\\\ {\text { 6) } g^{2}-h=(-7)^{2}-3=49-3=46}\end{array}

3 0
3 years ago
Micah is watching a TV program that is 2 hours long during the program there are six commercials that are each 90 sec. How many
Sergeu [11.5K]

Answer:

111 minutes

Step-by-step explanation:

step 1

Find out how long are the six commercial

Multiply the number of commercials by 90 seconds

so

90(6)=540\ sec

Convert to minutes

Remember that

1\ min=60\ sec

540\ sec=540/60=9\ min

step 2

Subtract the duration of six commercials from the duration of the program

Remember that

1\ h=60\ min

so

2\ h=2(60)=120\ min

therefore

120-9=111\ min

4 0
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The quotient of nine less than 3 times a number and four is 21how to translate into a sentence
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Hello,

Let's assume n the number searched.

nine less 3 times n is written 9-3n
 
\dfrac{9-3n}{4} =21\\&#10;==\ \textgreater \  9-3n=84\\&#10;==\ \textgreater \  -3n=75\\&#10;==\ \textgreater \  n=-25&#10;&#10;

8 0
3 years ago
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