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Andru [333]
3 years ago
8

0. A cylindrical tin has a radius of 3 cm. What is the shortest length of a string that can be wound once round the curved surfa

ce of the tin? (Taken = 3.14)​
Mathematics
1 answer:
madreJ [45]3 years ago
4 0

Answer: 18.84cm

Step-by-step explanation: 3 x 2 x 3.14 = 18.84cm

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Y = -11x - 25 ...........(i)<br> y = 5x - 7 ...............(ii)
valkas [14]

Answer:

3/2

Step-by-step explanation:

5x-7=-11x-25

5x+11x=-25+7

16x=18

x=18/16

x=3/2

6 0
3 years ago
A regular pentagon has side lengths of 10 cm and an
Fittoniya [83]

Answer: 172 square centimeters.

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a pentagon (A) = 1/2× 5s × a

Where:

s : side of the pentagon

a: apothem

Replacing with the values given and solving for A (area):

A =1/2 x (5 x10) x 6.88

A = 172 square centimeters.

Feel free to ask for more if needed or if you did not understand something.

7 0
3 years ago
Which is the value of this expression when p = - 2 and q = -1?
Elan Coil [88]

Answer: -4 is the answer

Step-by-step explanation:

4 0
3 years ago
A rancher wants to fence in an area of 1,000,000 square feet in a rectangular field and then divide it in half with a fence down
Svet_ta [14]

Answer:

  f(w) = 3w + 2,000,000/w

Step-by-step explanation:

We know that the area of a rectangle is the product of its length and width:

  A = LW

Filling in the given values lets us write an expression for the length of the field.

  1,000,000 = Lw

  L = 1,000,000/w

Since there are 3 fences of length w and two of length L, the total perimeter fence length is the sum ...

  f(w) = 3w + 2(1,000,000)/w

Combining the constants, we have a function for the perimeter fence length in terms of the width of the field:

  f(w) = 3w +2,000,000/w

5 0
3 years ago
What is the length of the diagonal of a square with side length 50\sqrt{2} cm? Express your answer in simplest form.
jenyasd209 [6]

Answer:

Length of diagonal = 100 cm

Step-by-step explanation:

Given:

Side length of square = 50\sqrt{2}   cm

Using pythagorean theorem:

Sum of squares of sides = Square of Diagonal

( 50\sqrt{2} )^2 + ( 50\sqrt{2} )^2 = x^2

Solving for x:

x^2 = 10000\\x = 100

Therefore,

Length of diagonal = 100 cm

5 0
4 years ago
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