-5-5/-1-1=
-10/-2=
5
y-5=5(x-1)
y-5=5x-5
y=5x+0
The length and the width of the rectangle are 20 and 14 inches respectively
<h3>How to find the length and width?</h3>
The given parameters are:
Length = 6 + Width
Perimeter = 68 inches
The perimeter of a rectangle is calculated as:
Perimeter = 2 * (Length + Width)
So, we have:
2 * (Length + Width) = 68
Divide both sides by 2
Length + Width = 34
Substitute Length = 6 + Width in Length + Width = 34
6 + Width + Width = 34
Evaluate the like terms
2 * Width = 28
Divide both sides by 2
Width = 14
Substitute Width = 14 in Length = 6 + Width
Length = 6 + 14
Evaluate
Length = 20
Hence, the length and the width of the rectangle are 20 and 14 inches respectively
Read more about perimeter at:
brainly.com/question/24571594
#SPJ1
Say your test is out of 100 and you 75 correct to calculate your percent you would go
75/100*100
/ = Divide
* = Times
True.
The Pythagorean theorem is a^2 + b^2 = c^2 where a^2 and b^2 are the two legs of the triangle (two sides connected by the right angle) and c is the hypotenuse (longest side, opposite the right angle).
To solve using the Pythagorean theorem, plug in sides AC and CB into a and b, then solve for c.
23^2 + 31^2 = c^2
529 + 961 = c^2
c^2 = 1490
c = √1490 = 38.601
I hope this helps!