Answer:
I believe it is B tell me if I am wrong please
In the problem with the white circle, x=100, in the problem with the blue circle, x might equal 165, but I'm not entirely certain. But I am certain about the first one.
Answer:
One edge of the cube is 5 cm, one edge of the square is 8 cm, so the edge of the cube is 3 cm shorter than the edge of the square.
Step-by-step explanation:
<h3 /><h3>The volume of the cube is found by the formula </h3><h2>V = s³, </h2><h3>where s is the side length (called the edge in this problem)</h3><h3>Since V = 125 cm³, we can take the cube root of 125 to find the edge length.</h3><h3>The cube root of 125 is 5, ( 5³ = 125)</h3><h3>So the edge of the cube is 5 cm</h3><h3 /><h3>The are of a square is found by the formula </h3><h2>A = s² , </h2><h3>where s is the side length (called the edge in this problem) </h3><h3>Since A = 64 cm², we can take the square root of 64 to find the edge length.</h3><h3>The square root of 64 is 8 (8² = 84)</h3><h3>So the edge of the square is 8cm</h3><h3 /><h3>Comparing the two edges tells us that the edge of the cube is 3cm shorter than the edge of the square.</h3>
The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 
<span>D) (-6, -5) is the answer. ope it helps!</span>
