Answer:
Step-by-step explanation:
<u>Trapezoid</u>
The trapezoid has been broken into two triangles and a rectangle. The two triangles both have the same dimensions, so both have the area ...
A = (1/2)bh = (1/2)(2 m)(5 m) = 5 m²
The rectangle has area ...
A = bh = (2 m)(5 m) = 10 m²
So, the total area of the trapezoid is ...
trapezoid area = 5 m² +10 m² +5 m²
trapezoid area = 20 m²
__
<u>Kite</u>
The kite has been broken into two triangles, so the area of each of them is ...
A = (1/2)bh
A = (1/2)(7 m)(3 m) = (21/2) m²
Then the area of the two halves of the kite will be ...
kite area = 2 × (21/2 m²)
kite area = 21 m²
__
The area of the trapezoid is <u>1 m² less than</u> the area of the kite.
<span>Let’s assume the number of problems as P
Student did his homework = (3/5) P + 8
Father did the homework = (1/5) P + 7
So the sum of the both equations is equal to P
=> (3/5) P + 8 + (1/5) P + 7 = P
=> (4/5) P + 15 = P
=> 4P + 75 = 5P
=> P = 75
Problems they solve together are 75 problems.</span>
X = 7/8
start by getting one x on the side of the equation.
Answer:
u1 = 1
u6 = 31
un = 1 + 6(n - 1)
Step-by-step explanation:
Sn = 3n² - 2n
u1 = S1
3(1)² - 2(1)
3 - 2
1
u6 = S6 - S5
[3(6)² - 2(6)] - [3(5)² - 2(5)]
96 - 65
31
un = a + (n - 1)d
u6 = a + 5d
31 = 1 + 5d
5d = 30
d = 6
un = 1 + 6(n - 1)
Answer:$3600 hope this helps
Step-by-step explanation:
