Answer:
by counting each individual atom and making sure the number of each kind of atom is the same in the reactants and the products. - This is the answer.
Explanation:
Answer:
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Explanation:
Answer:
okay with you if you want to
Answer:
![$ \phi_{21} = \frac{\phi_{12}}{2} $](https://tex.z-dn.net/?f=%24%20%5Cphi_%7B21%7D%20%3D%20%5Cfrac%7B%5Cphi_%7B12%7D%7D%7B2%7D%20%24)
Which means that the flux through each loop of the second coil is half as much as flux through each loop of first coil.
Explanation:
The flux through each loop of the first coil due to current in the second coil is,
![\phi_{12} = \phi](https://tex.z-dn.net/?f=%5Cphi_%7B12%7D%20%3D%20%5Cphi)
The number of loops in the first coil is
no. of loops = 2N
Total flux passing through the first coil is
![\phi_{12} = 2N\phi](https://tex.z-dn.net/?f=%5Cphi_%7B12%7D%20%3D%202N%5Cphi)
The flux through each loop of the second coil due to current in the first coil is,
![\phi_{21} = \phi](https://tex.z-dn.net/?f=%5Cphi_%7B21%7D%20%3D%20%5Cphi)
The number of loops in the second coil is
no. of loops = N
Total flux passing through the second coil is
![\phi_{21} = N\phi](https://tex.z-dn.net/?f=%5Cphi_%7B21%7D%20%3D%20N%5Cphi)
Comparing both
![\phi_{12} = \phi_{21} \\\\ 2N\phi = N\phi\\\\\phi_{21} = \frac{\phi_{12}}{2}](https://tex.z-dn.net/?f=%5Cphi_%7B12%7D%20%3D%20%5Cphi_%7B21%7D%20%5C%5C%5C%5C%202N%5Cphi%20%3D%20N%5Cphi%5C%5C%5C%5C%5Cphi_%7B21%7D%20%3D%20%5Cfrac%7B%5Cphi_%7B12%7D%7D%7B2%7D)
Which means that the flux through each loop of the second coil is half as much as flux through each loop of first coil.