A perpetual motion machine is (as the name implies) a machine that moves perpetually; it never stops. Ever. So if you created one today and set it going, it would keep on going until the Big Freeze<span>. Calling that “a long time” is an understatement of epic proportions</span>
Answer:
(a) 19.62 N
(b) Box moves down the slope
(c) 24.43 N
Explanation:
(a)
2 Kg box causes tension
![T=mgwhere m is mass, g is gravitational force taken as 9.81T=2*9.81 =19.62 N (b) Block mass of 4 Kg [tex]T'-mg sin \theta=0](https://tex.z-dn.net/?f=T%3Dmg%3C%2Fp%3E%3Cp%3Ewhere%20m%20is%20mass%2C%20g%20is%20gravitational%20force%20taken%20as%209.81%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3ET%3D2%2A9.81%20%3D19.62%20N%20%20%3C%2Fp%3E%3Cp%3E%28b%29%20%20%3C%2Fp%3E%3Cp%3EBlock%20mass%20of%204%20Kg%20%20%3C%2Fp%3E%3Cp%3E%5Btex%5DT%27-mg%20sin%20%5Ctheta%3D0)
hence 
where m is mass and g is gravitational force
T'=4*9.81 sin 35= 22.5071 N
Since T' is greater than 
, then the box moves down the slope
(c)
Acceleration a= 
When moving, the box will exert force T"= 
T"= 4*9.81 sin 35 +(4*0.48)= 24.43 N
<span>Mechanical association learning used by an actor to memorize his lines</span>
Answer:
The speed of the particle is 13767.35 m/s.
Explanation:
given the mass m = 6.67×10^-27 kg of particle and moving with a speed v. the momentum of the particle is given by P = m×v and the planck constant h = 6.63×10^-34 m^2×kg/s. the wavelength is λ = 7.22 pm ≈7.22×10^-12 m
The de Broglie wavelength is given by:
λ = h/P
λ = h/(m×v)
v = h/λ×m
= (6.63×10^-34)/[(7.22×10^-12)×(6.67×10^-27)]
= 13767.35 m/s
Therefore, the speed of the particle is 13767.35 m/s.
