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katovenus [111]
2 years ago
6

HEEEEELLLPPPPPP!!!!!!!!!!! PPPPPPPPPPPLLLEAASSEE!!!

Physics
1 answer:
o-na [289]2 years ago
4 0

Answer:

The arrows always start at the magnet's north pole and point towards its south pole. When two like-poles point together, the arrows from the two magnets point in OPPOSITE directions and the field lines cannot join up. So the magnets will push apart (repel).

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Astronomy
alina1380 [7]

Answer: B

Explanation:

X-rays coming into Earth's system from space are absorbed by the atmosphere. Telescopes that processes X-rays, therefore, are placed in orbit above the atmosphere

7 0
3 years ago
Read 2 more answers
Help please!
JulsSmile [24]

3. The sum of the players' momenta is equal to the momentum of the players when they're stuck together:

(75 kg) (6 m/s) + (80 kg) (-4 m/s) = (75 kg + 80 kg) v

where v is the velocity of the combined players. Solve for v :

450 kg•m/s - 320 kg•m/s = (155 kg) v

v = (130 kg•m/s) / (155 kg)

v ≈ 0.84 m/s

4. The total momentum of the bowling balls prior to collision is conserved and is the same after their collision, so that

(6 kg) (5.1 m/s) + (4 kg) (-1.3 m/s) = (6 kg) (1.5 m/s) + (4 kg) v

where v is the new velocity of the 4-kg ball. Solve for v :

30.6 kg•m/s - 5.2 kg•m/s = 9 kg•m/s + (4 kg) v

v = (16.4 kg•m/s) / (4 kg)

v = 4.1 m/s

7 0
2 years ago
When you stop at a railroad crossing at night, instead of correctly perceiving two red lights that flash alternately you may per
Nezavi [6.7K]
I'm pretty sure that there should be an options to choose. Anyway, I've seen this question before and I know that this is an example of <span>the phi phenomenon.</span>
7 0
3 years ago
Read 2 more answers
a car travelling at 50km/h from rest covers a distance of 10km in 40minutes. Calculate the acceleration​
Margarita [4]

Answer:

9.67\cdot 10^{-3}m/s^2

Explanation:

We can solve the problem by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the car in this problem:

u = 0 (it starts from rest)

v=50 km/h \cdot \frac{1000}{3600}=13.9 m/s is the final velocity

s = 10 km = 10 000 m is the displacement

Solving for a, we find:

a=\frac{v^2-u^2}{2s}=\frac{13.9^2}{2(10000)}=9.67\cdot 10^{-3}m/s^2

7 0
3 years ago
A 0.25-kg ball sits on the roof of a building that is 10 meters tall. Find the GPE. (Gravity = 9.8 on Earth)
Tasya [4]

Gravitational potential energy = mgh or mass times acceleration due to gravity times the height

Here the mass is 0.25kg, the height is 10m, and gravity is 9.8m/s^2 so...

GPE = (0.25)(10)(9.8)

GPE = 24.5 J

7 0
3 years ago
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