Solve for b<br> W=7b<br> Please help me solve this

The coordinate −6 has a weight of 3, and the<br> coordinate 2 has a weight of 1

Damm [24]

The weight average of the coordinates is -4

<h3>How to determine the weight average?</h3>

The complete question is given as:

The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. And we need to calculate the weight average

The given parameters are:

Coordinate -6 has a weight of 3
Coordinate 2 has a weight of 1.

The weight average is then calculated as:

Weight average = Sum of (Weigh * Coordinate)/Sum of Weights

So, we have:

Weight average = (-6 * 3 + 2 * 1)/(3 +1)

Evaluate the products

Weight average = (-18 + 2)/(3 +1)

Evaluate the sum

Weight average = -16/4

Evaluate the quotient

Weight average = -4

Hence, the weight average of the coordinates is -4

Read more about average at

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<u>Complete question</u>

The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. Calculate the weight average

4 0

2 years ago

What is the area of the shaded triangle?

Rzqust [24]

Answer:30

Step-by-step explanation: act like both of the triangles are there, that is a rectangle 6 times 10 equals 60. 60 divided by 2 is 30

6 0

3 years ago

$1500 at 9% for 2 years

kotykmax [81]

Answer:$270

Step-by-step explanation:

I=PRT

Interest=principal times rate times time

Principal=1500

Rate=9%=0.09

Time=2

I=1500 times 0.09 times 2

I=1500 times 0.18

I=270

Interest=270

Total is 1500+270=1770 total paid

8 0

3 years ago

A water storage tank has the shape of a cylinder with diameter 14 ft. It is mounted so that the circular cross-sections are vert

andrezito [222]

Answer:

percentage of the total capacity is 75.6%

Step-by-step explanation:

Hello! To solve this problem we follow the following steps

1. draw the complete scheme of the problem (see attached image)

2. To solve this problem we must find the area of the circular sector using the following equation.(c in the second attached image)

$A=\frac{R^2}{2} (\alpha -sin\alpha )$

$\alpha =2arccos(\frac{d}{R})$

3. observing the attached images we replace the values in the equations and find the area of the circular sector, remember that you must transform the angle to radians

$\alpha =2arccos(\frac{5}{7})=88.83$

$A=\frac{R^2}{2} (\alpha -sin\alpha )\\A=\frac{7^2}{2} (88.83-sen88.83)*\frac{\pi rad}{180} =37.57ft^2$

4.we calculate the area of the total circle (At), then subtract the area of the circular sector (Ac) to find the area occupied by water (Aw)

$At=\frac{\pi }{4} (14ft)^2=153.93ft^2$

Aw=At-Ac=153.93-37.57=116.36ft^2

5.Finally, we calculate the percentage that represents the water in the tank by dividing the area of the water over the total area of the tank

$\frac{116.36}{153.93} *100=75.6$

percentage of the total capacity is 75.6%

3 0

2 years ago

A triangle has vertices at coordinates $(1, 2), (7, 10)$ and $(1, 12)$. What is the number of units in the length of the shortes

const2013 [10]

Answer:

The number of units in the length of the shortest side of the triangle is 6.325 units or 2 sqrt 10.

7 0

3 years ago

Solve for b W=7b Please help me solve this