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Alex17521 [72]
3 years ago
8

FACTORISE: X3 + 3X2 +3X + 1

Mathematics
2 answers:
Ghella [55]3 years ago
7 0

Answer:

\Huge \boxed{(x+1)^3}

Step-by-step explanation:

x³ + 3x² + 3x + 1

Apply cube of sum rule :

      ⇒ a³ + 3a²b + 3ab² + b³ = (a + b)³

(x)³ + 3(x)²(1) + 3(x)(1)² + (1)³

 ⇒ a = x

 ⇒ b = 1

(x + 1)³

sineoko [7]3 years ago
6 0

Answer:

(x+1)(x+1)^2

Step-by-step explanation:

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(a^2 - 2a^2) - (3a^2 - 4a3)
pychu [463]

Answer:

-4a²+4a³

Step-by-step explanation:

6 0
2 years ago
Lines l and m are parallel. Parallel lines l and m are cut by transversals s and t. Clockwise from top left, the angles formed b
denis-greek [22]

Answer:

25 degrees

Step-by-step explanation:

In the picture attached, the lines and the angles are shown. There we can see that:

85° + 2x° + (x-10)° = 180°

75 + 3x = 180

x = (180 - 75)/3

x = 35°

∠3 and ∠(x-10)° are alternate interior angles, therefore they are congruent, so:

∠3 = x - 10

∠3 = 35 - 10

∠3 = 25°

4 0
2 years ago
Read 2 more answers
What is the missing constant term in the perfect square that starts with x2+18xx^2+18xx2+18xx, squared, plus, 18, x ?
katrin2010 [14]

Answer:

81

Step-by-step explanation:

Given the expression: x^2+18x

To make it a perfect square, we follow the following steps.

Divide the coefficient of x by 2

  • Coefficient of x=18, 18/2=9

Square It

  • 9 X 9=81

Add it to the expression

  • x^2+18x+81

This is written as a perfect square as: (x+9)^2

The constant term required therefore is 81.

4 0
3 years ago
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Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step
Lilit [14]

Answer: First option.

Step-by-step explanation:

The complete exercise is attached.

In order to solve this exercise, it is necessary to remember the following property:

The Multiplication property of Equality states that:

If\ a=b\ then\ a*c=b*c

In this case, the equation that Jada had is the folllowing:

-\frac{4}{9}=\frac{x}{108}

Jada needed to solve for the variable "x" in order to find its value.

The correct procedure to solve for for "x" is to multiply both sides of the equation by 108. Then, you get:

(108)(-\frac{4}{9})=(\frac{x}{108})(108)\\\\-48=x

As you can notice in the picture, Jada did not multiply both sides of the equation by 108, but multiplied the left side by -\frac{4}{9}<em>  </em>and the right side by -\frac{9}{4}.

Therefore,you can conclude that Jada should have multiplied both sides of the equation by 108.

3 0
2 years ago
Read 2 more answers
Solve the combined inequality x + 3 &gt; -5 and -4x ≥ -16 showing all of your work
ad-work [718]
Well for the first one you have to subtract 3 on both sides so that would make the equation x > -8 (because a negative subtracting a positive is basically a negative plus negative) and so your equations done.  For the second one you divide both ides by -4 so your equation would be x < 4 (the sign would be less then or qual to because you divided by a negative)
5 0
3 years ago
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