Look at the picture.
c.
1 unit right (+1); 2 units down (-2)
A(1, 3) → A'(1+1, 3-2) → A'(2, 1)
B(4, 5) → B'(4+1, 5-2) → B'(5, 3)
C(3, 1) → C'(3+1, 1-2) → C'(4, -1)
d.
(x, y) → (x + 1, y - 2)
The set of all months that contains less than 31 days is; {February, April, June, September, November}.
<h3>What is the set of all months that contain less than 31 days?</h3>
It follows from the task content that the set whose elements are to be determined is characterized by containing less than 31 days.
On this note, it follows that the elements of the set are; February (28/29 days), April (30 days), September (30 days), June (30 days) and November (30 days).
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Answer:
-x^2+4x+6
Step-by-step explanation:
f(x) = 4x+1
g(x) = x^2 - 5
(f-g) (x) = 4x+1 - ( x^2 - 5)
Distribute the minus sign
= 4x+1 - x^2 +5
Combine like terms
= -x^2+4x+6
Answer:
see explanation
Step-by-step explanation:
To find the zeros equate g(x) to zero, that is
(x - 2)(3x + 3) = 0
Equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2
3x + 3 = 0 ( subtract 3 from both sides )
3x = - 3 ( divide both sides by 3 )
x = - 1
Hence
smaller x = - 1
larger x = 2
