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melamori03 [73]
3 years ago
6

Find the area and perimeter ​

Mathematics
1 answer:
pshichka [43]3 years ago
3 0

Answer:

your area is 13 and the perimeter look at the green one

Step-by-step explanation:

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A pizza is cut into 8 equal pieces. A person who eats 1/2 of one piece eats what fraction of the pizza?
Rudik [331]
The person eats 1/16 of the pizza
5 0
3 years ago
Juan has 20 books to sell. He sells the books for $15 each.
Anastaziya [24]

Answer:

Well u would multiply 20 x 15 to find out the highest if the range which is 300 . So that knocks it down to B or D. But since they're $15 each, It would be based of the multiples of 15 making your answer B .

The range is all the y values.....or the f(x) values .

So the practical range would be the multiples of 15 between 0 and 300,Inclusive .

<h2>Hope this helps you!! </h2>

5 0
2 years ago
Jake has five cats and then he finds ten more cats how many does jake have after he loses 11 cats
AleksandrR [38]

jake has 5 cats

then he finds 10 cats

jake now has 5+10 = 15 cats

now he loses 11 cats

15 -11 =4

jake now has 4 cats

8 0
3 years ago
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A chameleon's tongue is twice the length of its body.
Softa [21]

Answer:

52 inches

Step-by-step explanation:

26 x 2 is 52

6 0
2 years ago
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A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat
Ivanshal [37]

We are told that a population of insects grows exponentially and we are given a table of data about insect population growth. We are asked to find population of insects at the end of week 11.        

The initial insect population is 20 and at the end of 1st week population increases to 30.

Let us find growth percentage of insect  population,

\text{Growth percentage}=\frac{\text{Difference}}{Actual} \cdot100

\text{Growth percentage}=\frac{\text{30-20}}{20} \cdot100

\text{Growth percentage}=\frac{\text{10}}{20} \cdot100

\text{Growth percentage}=0.5 \cdot100=50

We can see that insect population is growing at rate of 50% per week.

Now let us write an exponential function for our population.

P(w)=20(1+0.50)^{w}, where P(w) represents population at the end of w weeks.

Let us substitute w=11 in our function to find insect population at the end of 11 weeks.

P(11)=20(1+0.50)^{11}

P(11)=20(1.50)^{11}

P(11)=20\cdot 86.49755859375

P(11)=1729.951171875\approx 1730

Therefore, population of insects at the end of 11th week will be 1730.  



7 0
3 years ago
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