(x+9)(x+8) = x^2 +17x + 72
(x- 7)(x+8) = x^2 + x - 72
(x- 5)(x- 6) = x^2 -11x + 30
(2x + 3)(3x+2) = 6x^2 + 13x +6
(5x - 4)(2x-5) = 10x^2 - 33x + 20
(x-4)^2 = x^2 -8x + 16
(2x+1)^2 = 4x^2 +4x + 1
(4x+3)(4x-3) = 16x^2 - 9
Answer:
X=-1/2
Step-by-step explanation:
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100 2 zeros...............
Function defines relationship between variables. The value of the f[g(x)] when the value of f(x)=6x+11 and g(x)=x²+6 is f[g(x)]= 36x²+47.
<h3>What is a function?</h3>
A function assigns the value of each element of one set to the other specific element of another set.
Given to us
f(x) = 6x + 11
g(x) = x² + 6
As we know the two functions, given to us f(x) = 6x + 11, therefore substitute the value of x as g(x) in order to find the value of f[g(x)] ,
![f(x) = 6x + 11\\\\f[g(x)] = 6(x^2 + 6) + 11\\\\f[g(x)] = 6x^2 + 36 + 11\\\\f[g(x)] = 6x^2 + 47](https://tex.z-dn.net/?f=f%28x%29%20%3D%206x%20%2B%2011%5C%5C%5C%5Cf%5Bg%28x%29%5D%20%3D%206%28x%5E2%20%2B%206%29%20%2B%2011%5C%5C%5C%5Cf%5Bg%28x%29%5D%20%3D%206x%5E2%20%2B%2036%20%2B%2011%5C%5C%5C%5Cf%5Bg%28x%29%5D%20%3D%206x%5E2%20%2B%2047)
Hence, the value of the f[g(x)] when the value of f(x)=6x+11 and
g(x)=x²+6 is f[g(x)]= 36x²+47.
Learn more about Function:
brainly.com/question/5245372