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SCORPION-xisa [38]
3 years ago
13

Can anyone help me with this ?

Mathematics
1 answer:
Setler [38]3 years ago
7 0

hope it can help you,x=-5,x=2

calculation is given in the picture

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Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
3 years ago
Read 2 more answers
A circular swimming pool has a diameter of the 26 feet.
kherson [118]
Hey there! :)

The formula for finding area of circles is: π · r²

<em>Remember that radius is half the diameter. To find radius when the diameter is given, divide by 2</em>

d = 26

26 ÷ 2 = 13
_____________________________________________________________

π · r²

r = 13
13² = 13 × 13 = 169

169 × 3.14 = 530.66 = 530.7

The area of the swimming pool is 530.7 ft²

Hope this helps :)
7 0
3 years ago
Read 2 more answers
Given h(x) = x2 – 5x + 7, find the following.<br> a. h(2)<br> b.h(-5)<br> c. h(-8)
azamat

Answer:

Step-by-step explanation:

hello :

h(x) = x² – 5x + 7

h(-2) = (-2)² – 5(-2) + 7 =4+10+7 =21

h(-5) = (-5)² – 5(-5) + 7= 25+25+7 =57

h(-8) = (-8)² – 5(-8) + 7 = 64+40+7=111

5 0
3 years ago
The length of a rectangular garden is 17 feet longer than its width. If the area of the garden is 234 square feet, what are the
kifflom [539]

Answer:

The garden is 9 feet wide and 26 feet long.

Step-by-step explanation:

L = W+17

area = LW = 234

(W+17)W = 234

W²+17W-234 = 0

Quadratic formula

W = [-17 ± √(17² – 4·1(-234))] / [2·1]

 = [-17 ± √1225] / 2

 = [-17 ± 35] /2

 = -26, 9

-26 is an extraneous solution

W = 9

L = W+17 = 26

The garden is 9 feet wide and 26 feet long.

3 0
3 years ago
Mrs Smith is completing a mathematics problem. She knows when 6 is added to four times a number, the result is 50. What would be
Lesechka [4]

EXPLANATION:

-To formulate an equation, you must first know what data the exercise gives us to locate them correctly.

data:

-6 that must be added to a number.

-four times a number that is equal to 4x

-a result that is equal to 50

Now with these data we formulate the equation:

\begin{gathered} \text{Equation:} \\ 6+4x=50;\text{  } \end{gathered}

if we solve the equation we have:

\begin{gathered} 6\text{ }+4x=50 \\ 4x=50-6 \\ 4x=44 \\ x=\frac{44}{4} \\ x=-\frac{22}{2} \\ x=\text{ }-11 \end{gathered}

6 0
1 year ago
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