Co-Ordination Difficulty: ...
Waste of Resources: ...
Larger Interests of the Enterprise Neglected: ...
Emergency Decision not Possible: ...
Lack of Qualified Managers: ...
Certain Activities Decentralization not Possible:
```
<ul>
<li>item1</li>
<li>item2</li>
</ul>
```
It's the same for ol.
Answer:
The code for the function is given below in Python language
Explanation:
def append_string_to_file(filename, text):// function takes the filename // and text to append
f = open(filename, 'a')
f.write(text) //function part that writes the text
f.close() //closing the file using the explicit close function
Answer:
For this wild card mask 0.0.15.255 the ACE IP address will be 172.16.47.254
Explanation:
ACL is the access control list that is used to enlist the ip addresses that allowed or restricted to access the network. ACE is an IP address from the list ACL that has all rules and regulations related to access of network. The ACE could be in the range of IP address in ACL. ACL can be calculated with the help of initial IP address adding with wild card mask.
So
Initial IP address is = 172.16.32.0
Wild card mask =0.0.15.255
by adding above values we can find the last IP address of ACL.
after addition
Final IP address is = 172.16.47.255
The options that are available with question, Only option between the range is 172.16.47.254. So we can say that This is the only ACE IP address in options.
Please Help! Unit 6: Lesson 1 - Coding Activity 2
Instructions: Hemachandra numbers (more commonly known as Fibonacci numbers) are found by starting with two numbers then finding the next number by adding the previous two numbers together. The most common starting numbers are 0 and 1 giving the numbers 0, 1, 1, 2, 3, 5...
The main method from this class contains code which is intended to fill an array of length 10 with these Hemachandra numbers, then print the value of the number in the array at the index entered by the user. For example if the user inputs 3 then the program should output 2, while if the user inputs 6 then the program should output 8. Debug this code so it works as intended.
The Code Given:
import java.util.Scanner;
public class U6_L1_Activity_Two{
public static void main(String[] args){
int[h] = new int[10];
0 = h[0];
1 = h[1];
h[2] = h[0] + h[1];
h[3] = h[1] + h[2];
h[4] = h[2] + h[3];
h[5] = h[3] + h[4];
h[6] = h[4] + h[5];
h[7] = h[5] + h[6];
h[8] = h[6] + h[7]
h[9] = h[7] + h[8];
h[10] = h[8] + h[9];
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
if (i >= 0 && i < 10)
System.out.println(h(i));
}
}