A triangle has sides of LaTeX: 1\frac{1}{6}1 1 6 inches, LaTeX: 1\frac{1}{3}1 1 3 inches, and LaTeX: 1\frac{2}{3}1 2 3 inches. W
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The general form of a solution of the differential equation is already provided for us:
where . We now want to find a solution
such that
and
. Therefore, all we need to do is find the constants
and
that satisfy the initial conditions. For the first condition, we have:
For the second condition, we need to find the derivative first. In this case, we have:
Therefore:
This means that we must solve the following system of equations:
If we add the equations above, we get:
If we now substitute into either of the equations in the system, we get:
This means that the solution obeying the initial conditions is:
Indeed, we can see that:
which do correspond to the desired initial conditions.