Question

title="\frac{2+h}{9}+\frac{h-1}{3}=\frac{1}{3}" alt="\frac{2+h}{9}+\frac{h-1}{3}=\frac{1}{3}" align="absmiddle" class="latex-formula">

Answer 1

Step-by-step explanation:

Multiply both sides by 9 and you will get

$2 + h + 3(h - 1) = 3$

or

$2 + h + 3h - 3 = 3$

Solving for h, we get

$4h = 4 \Rightarrow h = 1$