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zaharov [31]
2 years ago
8

Complete the equation so that it has infinitely many solutions. 2(2x + 1) = 2 _____

Mathematics
1 answer:
ollegr [7]2 years ago
5 0

Answer:

2(2x + 1) = 2(2x + 1)

Hope this helps

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Answer: I not super sure, but I think you are supposed to put the equations on each side of the table. Your end result should be 2x to the second -5x-3.

Step-by-step explanation:

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3 years ago
Does x equal if the problem is negative x -4x - 7 equals 5 negative 2X
Sphinxa [80]

Answer:

X = - 4

Step-by-step explanation:

Given in problem

- x -4x - 7 = 5 -2x

Or, -5x - 7 = 5- 2x

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Or, -3x = 12

Or, x = - \frac{12}{3}

∴ X = - 4    Answer

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4 years ago
Why does a radical function with an even index only appear on one sode of the x-axis while a radical woth an odd index appears o
Vladimir79 [104]

Consider the equation y = x^2. No matter what x happens to be, the result y will never be negative even if x is negative. Example: x = -3 leads to y = x^2 = (-3)^2 = 9 which is positive.

Since y is never negative, this means the inverse x = sqrt(y) has the right hand side never be negative. The entire curve of sqrt(x) is above the x axis except for the x intercept of course. Put another way, we cannot plug in a negative input into the square root function for this reason. This similar idea applies to any even index such as fourth roots or sixth roots.

Meanwhile, odd roots such as a cube root has its range extend from negative infinity to positive infinity. Why? Because y = x^3 can have a negative output. Going back to x = -3 we get y = x^3 = (-3)^3 = -27. So we can plug a negative value into the cube root to get some negative output. We can get any output we want, negative or positive. So the range of any radical with an odd index is effectively the set of all real numbers. Visually this produces graphs that have parts on both sides of the x axis.

3 0
3 years ago
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