Answer: -3
Step-by-step explanation:
Since we are given the value of r, we can plug that value into the expression and solve.
15+6(-3) [multiply]
15-18 [subtract]
-3
Now, we know that the expresison is equal to -3.
X² + xy - 2x - 2y
The first thing would be to break the polynomial up into pairs.
(x² + xy) + (-2x -2y)
Then you can factor them individually.
(x² + xy)
Both numbers have x in common, so you can factor it out and get
x(x + y)
Then you factor the other pair,
(-2x -2y)
Both numbers have -2 in them, so you can factor it out and get
-2(x + y)
Now your two pairs are
[x (x + y)] and [-2 (x + y)]
Notice that the two terms in parentheses are the same, so you can get rid of one and combine the two outside terms to get a final answer of
(x - 2)(x + y)
Answer:
y = -x - 1
Step-by-step explanation:
y = mx + b
<u>slope (m):</u> Since the line is going downhill, the slope will be negative
slope = rise / run
slope = 1 / 1
slope = 1
m = -1
<u>y - intercept (b):</u> this when x = 0, the line is crossing the vertical line (y-axis)
b = -1
so y = mx + b is
b = -1, m = -1
y = (-1)x + (-1)
Answer:
- the given dimension was used as the radius
- 5.57 m³
Step-by-step explanation:
The volume of a sphere can be found using the formula ...
V = 4/3πr³ . . . . . where r is the radius
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The figure points to a diameter line and indicates 2.2 m. The arrowhead is in the middle of a radius line, making it easy to interpret the dimension as the radius of the sphere.
If 2.2 m is used as the radius, the volume is computed to be ...
V = 4/3π(2.2 m)³ ≈ 44.58 m³
This agrees with your friend's volume, suggesting the diameter was used in place of the radius in the computation.
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The correct volume, using 2.2 m as the diameter, is ...
V = 4/3π(1.1 m)³ ≈ 5.57 m³
Let 
be the unknown number. So, three times that number means 
, and the square of the number is 
We have to sum 528 and three times the number, so we have 
Then, we have to subtract this number from , so we have
The result is 120, so the equation is
This is a quadratic equation, i.e. an equation like 
. These equation can be solved - assuming they have a solution - with the following formula
If you plug the values from your equation, you have
So, the two solutions would be
But we know that x is positive, so we only accept the solution 
