9514 1404 393
Answer:
- 75 adult tickets
- 125 child tickets
Step-by-step explanation:
Let 'a' represent the number of adult tickets sold. Then (200-a) is the number of child tickets sold, and the revenue is ...
8a +5(200 -a) = 1225
3a = 225 . . . . . . . . . . subtract 1000, simplify
a = 75 . . . . . . . . . . . . .divide by 3
200 -a = 125
75 adult ($8) and 125 child ($5) tickets were sold.
__
<em>Additional comment</em>
The question asked here is "how many tickets did Kay sell?" The second line of your problem statement tells you the answer: "Kay sold 200 tickets ...". We have assumed that you are interested in the breakdown of tickets sold, even though that is not the question that is asked here.
27 degrees add four then 23 and you get 27
I need a picture so that I could see the diagram
Order of the people does not affect the total number of ways. Thus, we use combinations.
Total combinations: 20C5 = 15,504 ways.
Answer:42
Step-by-step explanation:
2(3+6)+(8)(3)
=(2)(9)+(8)(3)
=18+(8)(3)
=18+24
=42
leave a like if this helped please
