A student formed a pattern in which each term is represented by a sum. The first four terms of the pattern are shown below

Is y = 5(1.04)* A. growth or B. decay?

Ilya [14]

Answer:

growth

Step-by-step explanation:

6 0

3 years ago

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Write an equation of the line that passes through the given point and is parallel to the given line.

Margaret [11]

Answer:

Part 40) $y=-2x+9$

Part 41) $y=5x+6$

Part 42) $y=\frac{2}{3}x+\frac{4}{3}$

Step-by-step explanation:

Remember that

If two lines are parallel, then their slopes are the same

Part 40) Write an equation of the line that passes through the given point

and is parallel to the given line

we have

Point (4,1)

Given line y=-2x+7

step 1

Find the slope of the given line

The given line is a equation of the line in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

so

The slope of the given line is

$m=-2$

step 2

Find the y-intercept b

we have

$m=-2$

$(4,1)$

substitute in the linear equation

$1=(-2)4+b$

solve for b

$b=1+8$

$b=9$

step 3

Find equation of the line that passes through the given point and is parallel to the given line

we have

$m=-2$

$b=9$

substitute

The equation of the line is

$y=-2x+9$

Part 41) Write an equation of the line that passes through the given point

and is parallel to the given line

we have

Point (0,6)

Given line y=5x-3

step 1

Find the slope of the given line

The given line is a equation of the line in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

so

The slope of the given line is

$m=5$

step 2

Find the y-intercept b

$b=6$ ----> because the y-intercept is the point (0,6) (value of y when the value of x is equal to zero)

step 3

Find equation of the line that passes through the given point and is parallel to the given line

we have

$m=5$

$b=6$

substitute in the linear equation

$y=5x+6$

Part 42) Write an equation of the line that passes through the given point

and is parallel to the given line

we have

Point (-5,-2)

Given line y=(2/3)x+1

step 1

Find the slope of the given line

The given line is a equation of the line in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

so

The slope of the given line is

$m=\frac{2}{3}$

step 2

Find the y-intercept b

we have

$m=\frac{2}{3}$

$(-5,-2)$

substitute in the linear equation

$-2=(\frac{2}{3})(-5)+b$

solve for b

$-2=-\frac{10}{3}+b$

$b=-2+\frac{10}{3}$

$b=\frac{4}{3}$

step 3

Find equation of the line that passes through the given point and is parallel to the given line

we have

$m=\frac{2}{3}$

$b=\frac{4}{3}$

substitute

The equation of the line is

$y=\frac{2}{3}x+\frac{4}{3}$

3 0

2 years ago

The ratio of the area between a small square of land and a large squareof land is 3: 7. Given that the total area of the two squ

lakkis [162]

Given:

The ratio of the area between a small square of land and a large square

of land is 3: 7.

Total area of the two squares of land (in sq. meter) is 4000.

Required:

The area of each square of land.

Answer:

We have the ratio of the area between a small square of land and a large square of land is 3: 7.

Let

$x^$

be the area of the square of land.

Then their ratio is given by,

$3x^:7x^$

Also given that the total area of the two squares of land (in sq.meter) is

4,000.

The area of

Therefore,

$\begin{gathered} 3x^+7x^=4000 \\ \Rightarrow10x^=4000 \\ \Rightarrow x^=400 \\ \end{gathered}$

Therefore,the area of small square (in sq. meter) is,

$3x=3(400)=1200$

and the area of large square (in sq. meter) is,

$7x=7(400)=2800$

Final Answer:

The area of small and large square respectively (in sq. meter) is,1200 and 2800.

7 0

7 months ago

Decide whether the relation is a function: {(-3, 7), (1, -8), (6, -6), (7-8), (12, 2)}

lakkis [162]

Answer:

It is a function

Step-by-step explanation:

A function is of the form:

$\left[\begin{array}{c}x_1&x_2&x_3\\-&-&-\\x_n\end{array}\right]$ $\left[\begin{array}{c}y_1&y_2&y_3\\-&-&-\\y_n\end{array}\right]$

Where each of the x values must be distinct.

The x values are referred to as domain while the y values are called range.

Having said that, the given data can be represented as follows:

$\left[\begin{array}{c}-3&1&6\\7&12\end{array}\right]$ ----------- $\left[\begin{array}{c}7&-8&-6\\-8&2\end{array}\right]$

From the representation above, none of the x values are repeated.

Hence, it is a function

6 0

2 years ago

Part A

Mkey [24]

Answer:

4 1/2

Step-by-step explanation:

4 1/2

3 0

2 years ago

Read 2 more answers