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12345 [234]
3 years ago
15

Ok so I have fraction box with 1/20 20/25 2/3 and 5/4 the question provide a reason each fraction doesn't belong and to plot the

fractions on a number line
Mathematics
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:C on edge

Step-by-step explanation:

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You have one type of nut that sells for $2.80/lb and another type of nut that sells for $9.60/lb. You would like to have 20.4 lb
max2010maxim [7]

Answer:11.396Ibs of nuts that cost $9.60/Ib and 9.014Ibs that cost $2.80/Ib

Step-by-step explanation:

First we find the cost of the supposed mixture we are to get by selling it $6.60/Ib which weighs 20.41Ibs

Which is 6.6 x 20.41 = $134.64

Now we label the amount of mixture we want to get with x and y

x = amount of nuts that cost $2.8/Ib

y = amount of nuts that cost $9.6/Ib

Now we know the amount of mixture needed is 20.41Ibs

So x + y = 20.41Ibs

And then since the price of the mixture to be gotten overall is $134.64

We develop an equation with x and y for that same amount

We know the first type of nut is $2.8/Ib

So for x amount we have 2.8x

For the second type of nut that is $9.6/Ib

For y amount we have 9.6y

So adding these to equate to $134.64

2.8x + 9.6y = 134.64

So we have two simultaneous equations

x + y = 20.41 (1)

2.8x + 9.6y = 57.148 (2)

We can solve either using elimination or factorization method

I'm using elimination method

Multiplying the first equation by 2.8 so that the coefficient of x for both equations will be the same

2.8x + 2.8y = 57.148

2.8x + 9.6y = 134.64

Subtracting both equations

-6.8y = -77.492

Dividing both sides by -6.8

y = -77.492/-6.8 =11.396

y = 11.396Ibs which is the amount of nuts that cost $9.6/Ib

Putting y = 11.396 in (1)

x + y = 20.41 (1)

x +11.396 = 20.41

Subtract 11.396 from both sides

x +11.396-11.396 = 20.41-11.396

x = 9.014Ibs which is the amount of nuts that cost $2.8/Ibs

8 0
3 years ago
Please help me fill in the blanks again
Artemon [7]

Answer:

Comp

84

69

Supp

166

71

3 0
3 years ago
Read 2 more answers
What is the graph for {3x+5y<10 {x-y<=1
Nostrana [21]
Sounds to me as tho you are to graph 3x+5y<10, and that after doing so you are to restrict the shaded answer area created by the "constraint" inequality x≤y+1.    OR x-1 ≤ y   OR  y≥x-1.  If this is the correct assumption, then please finish the last part of y our problem statement by typing   {x-y<=1}.

First graph 3x+5y = 10, using a dashed line instead of a solid line.

x-intercept will be 10/3 and y-intercept will be 2.  Now, because of the < symbol, shade the coordinate plane BELOW this dashed line.

Next, graph y=x-1.  y-intercept is -1 and x intercept is 1.  Shade the graph area ABOVE this solid line.

The 2 lines intersect at (1.875, 0.875).  To the LEFT of this point is a wedge-shaped area bounded by the 2 lines mentioned.  That wedge-shaped area is the solution set for this problem.
6 0
3 years ago
Some body please help me!!!!!!
VladimirAG [237]

Surface area of a cube = 486 square inches

Solution:

Given each side of a cube = 9 inches

Net of a cube has 6 squares.

Area of square = side × side

Area of 1 square = 9 × 9 = 81 square inches

Surface area of a cube = Area of 6 squares

                                      = 6 × (side × side)

                                      = 6 × 81

                                      = 486 square inches

Hence, surface area of a cube is 486 square inches.

7 0
3 years ago
What is 2x - 1 &lt; 3? Solve
Licemer1 [7]

Answer:

x<2

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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