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12345 [234]
3 years ago
15

Ok so I have fraction box with 1/20 20/25 2/3 and 5/4 the question provide a reason each fraction doesn't belong and to plot the

fractions on a number line
Mathematics
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:C on edge

Step-by-step explanation:

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Help plz!! Will give brainliest
r-ruslan [8.4K]

Answer:

C is the sorrect because those both lines are equal

Step-by-step explanation:

6 0
3 years ago
1 matrix question help (with picture)
Dominik [7]

Answer:

  a = 9/2

Step-by-step explanation:

In order for the equation to be true, the value of the scalar multiplier must be ...

  15/3 = -10/-2 = 35/7 = 5

So, you're solving ...

  (2/3)a + 2 = 5

  (2/3)a = 3 . . . . . . subtract 2

  a = 9/2 . . . . . . . . multiply by 3/2

3 0
4 years ago
-3/5 ÷1/5 = ? please solve this fraction question by dividing.
Finger [1]
The answer should be -3, I can explain it if you want.
5 0
4 years ago
Read 2 more answers
11. ¿Es mayor 1/4 que 0.50? Justifica tu pregunta​
musickatia [10]

Eh yo creo que no, si estoy mal los siento

3 0
3 years ago
Suppose that x has a binomial distribution with n = 201 and p = 0.45. (Round np and n(1-p) answers to 2 decimal places. Round yo
ycow [4]

Answer:

a) It can be used because np and n(1-p) are both greater than 5.

Step-by-step explanation:

Binomial distribution and approximation to the normal:

The binomial distribution has two parameters:

n, which is the number of trials.

p, which is the probability of a success on a single trial.

If np and n(1-p) are both greater than 5, the normal approximation to the binomial can appropriately be used.

In this question:

n = 201, p = 0.45

So, lets verify the conditions:

np = 201*0.45 = 90.45 > 5

n(1-p) = 201*(1-0.45) = 201*0.55 = 110.55 > 5

Since both np and n(1-p) are greater than 5, the approximation can be used.

3 0
3 years ago
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