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skelet666 [1.2K]
2 years ago
13

What is the binary number for 5?

Computers and Technology
1 answer:
Softa [21]2 years ago
8 0

Answer:

the binary code for "5" is 00000101

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TV show information can either keep track of the number of viewers per show or the name of a show. Information is kept in a file
Elza [17]

Answer:

See explaination for Program source code.

Explanation:

The program source code below.

#include <iostream>

#include <fstream>

#include <vector>

using namespace std;

class Show

{

private:

string title;

int viewers;

public:

Show()

{

this->title = "";

this->viewers = 0;

}

Show(string title, int viewers)

{

this->title = title;

this->viewers = viewers;

}

string getTitle(){ return this->title; }

int getViewers(){ return this->viewers; }

};

int main()

{

vector<Show> shows;

vector<string> titles;

vector<int> viewers;

ifstream inFile1("file1.txt");

ifstream inFile2("file2.txt");

string line1, line2;

if(!inFile1.is_open() || !inFile2.is_open())

{

cout << "Either of the files could not be found!\n";

exit(0);

}

getline(inFile1, line1);

if(line1.compare("Show") == 0)

{

while(getline(inFile1, line1))

{

titles.push_back(line1);

}

inFile1.close();

}

getline(inFile2, line2);

if(line2.compare("Viewer") == 0)

{

while(getline(inFile2, line2))

{

viewers.push_back(stod(line2));

}

inFile2.close();

}

for(int i = 0; i < titles.size(); i++)

{

shows.push_back(Show(titles[i], viewers[i]));

}

// display all the show details

cout << "\nALL SHOWS:\n----------\n";

for(Show show : shows)

{

cout << "Title: " << show.getTitle() << ", Number of viewers: " << show.getViewers() << endl;

}

cout << endl;

return 0;

}

See attachment for output

3 0
3 years ago
Use the Internet to gather information on four filesystems compatible with Linux. For each filesystem, list the situations for w
marta [7]
If fhun gftrfjjtcbjjbsufcghtfghyrssfbkoire crazy ahh young man
7 0
3 years ago
According to Amdahl's Law, what is the speedup gain for an application that is 60% parallel and we run it on a machine with 4 pr
rodikova [14]

With four processing cores, we get a speedup of 1.82 times.

<h3>What is Amdahl's Law?</h3>

Amdahl's law exists as a formula that provides the theoretical speedup in latency of the implementation of a task at a fixed workload that can be expected of a system whose resources exist improved.

Amdahl's law exists that, in a program with parallel processing, a relatively few instructions that hold to be completed in sequence will have a limiting factor on program speedup such that adding more processors may not complete the program run faster.

Amdahl's law stands also known as Amdahl's argument. It is utilized to find the maximum expected progress to an overall system when only part of the system exists improved. It is often utilized in parallel computing to indicate the theoretical maximum speed up utilizing multiple processors.

Hence,  With four processing cores, we get a speedup of 1.82 times.

To learn more about Amdahl's Law refer to:

brainly.com/question/16857455

#SPJ4

6 0
2 years ago
A _______________ is a field that contains data unique to a record.
Andru [333]

A primary key is a field that contains data unique to a record

8 0
3 years ago
Given the lists list1 and list2, not necessarily of the same length, create a new list consisting of alternating elements of lis
tester [92]

Answer:

The following code is written in Python Programming Language.

Program:

list1=[1,2,3]

 # initialized the list type variable

list2=[4,5,6,7,8]

  # initialized the list type variable

list3=[]

   # initialized the empty list type variable

for j in range(max(len(list1), len(list2))):   #set for loop

 if j<len(list1):

  #set if statement

   list3.append(list1[j])

  #value of list1 appends in list3  

 if j<len(list2):

   #set if statement

   list3.append(list2[j])

  #value of list2 append in list3

print(list3)    #print the list of list3

Output:

[1, 4, 2, 5, 3, 6, 7, 8]

Explanation:

Here, we define three list type variables "list1", "list2", "list3" and we assign value in only first two variables "list1" to [1, 2, 3] and "list2" to [4, 5, 6, 7, 8] and third list is empty.

Then, we set the for loop and pass the condition inside it we pass two if conditions, in first one we compare the list1 from variable "j" inside it the value in list1 will append in list3, and in second one we compare "j" with list two and follow the same process.

After all, we print the list of the variable "list3".

5 0
3 years ago
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