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3 years ago

10

You can precede a subquery with the ___ operator to create a conditiion that is true if one or more rows are obstained when the

subquery is executed

Computers and Technology

1 answer:

nadezda [96]3 years ago

8 0

I'm not sure about context of this question, but i think answer is "OR" ("||" in many programming languages).

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LAB: Parsing dates Complete main() to read dates from input, one date per line. Each date's format must be as follows: March 1,

Vladimir [108]

The python code which can be used to read dates from input, one date per line and each date's format must be as follows: March 1, 1990, is:

<h3>Python code</h3>

import datetime

inputs = []

result = []

#read the inputs

date = input()

inputs.append(date)

while not date == "-1":

date = input()

inputs.append(date)

#check if the input is in the correct format and convert it.

for date_text in inputs:

try:

date_text = datetime.datetime.strptime(date_text,"%d %B, %Y")

result.append(date_text.strftime("%d/%m/%Y"))

except ValueError:

pass

print(*result, sep = "\n")

The above code would parse the string and extract the date. The split() method was used to break the input into tokens.

Read more about python programming here:

brainly.com/question/27666303

#SPJ1

6 0

1 year ago

If you're driving a car and know there's a motorcyclist around you, you should______. A. Not change your driving B. Check your b

Sedaia [141]

b check your blind spots frequently i guess not sure

5 0

2 years ago

Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type

sattari [20]

Solution :

#include $$$$

#include $$$$

#include $$$$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal $\text{To}$ Binary(char* hexdec)

{

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$ (sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

4 0

2 years ago

PLEASE SOMEONE ANSWER THIS

maw [93]

Maybe 7411 or someones birthday in the family

3 0

2 years ago

Read 2 more answers

When you sustain program implementation by staying true to the original design, it is termed A. Goals and objectives B. Program

Naya [18.7K]

Answer:

Program fidelity

Explanation:

7 0

2 years ago