Answer: The ball hits the ground at 5 s
Step-by-step explanation:
The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:
(1)
Where 
models the height of the ball in meters and 
the time.
Now, let's find the time when the ball Sara kicked hits the ground (this is when 
):
(2)
Rearranging the equation:
(3)
Dividing both sides of the equation by 
:
(4)
This quadratic equation can be written in the form 
, and can be solved with the following formula:
(5)
Where:
Substituting the known values:
(6)
Solving we have the following result:
This means the ball hit the ground 5 seconds after it was kicked by Sara.
Answer:
A
Step-by-step explanation:
(fg)(x) = f(x) × g(x)
= (x - 8)(x² + x - 1)
Each term in the second factor is multiplied by each term in the first factor, that is
x(x² + x - 1) - 8(x² + x - 1) ← distribute both parenthesis
= x³ + x² - x - 8x² - 8x + 8 ← collect like terms
= x³ - 7x² - 9x + 8 → A
There are no restrictions on the domain.
Answer:
-4
Step-by-step explanation:
[√2(cos(3π/4) + i sin(3π/4))]⁴
(√2)⁴ (cos(3π/4) + i sin(3π/4))⁴
4 (cos(3π/4) + i sin(3π/4))⁴
Using De Moivre's Theorem:
4 (cos(4 × 3π/4) + i sin(4 × 3π/4))
4 (cos(3π) + i sin(3π))
3π on the unit circle is the same as π:
4 (cos(π) + i sin(π))
4 (-1 + i (0))
-4
I think the answer would be <span>A=0.85
B=(1 - 0.15)d
C=85d
D=0.85d</span>
1) 12p+12q 2) 11p-11q 3)2p-10q
