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Rus_ich [418]
3 years ago
9

Use compatible numbers to estimate the quotient? 474÷9

Mathematics
1 answer:
olga55 [171]3 years ago
8 0
474 divided by 9 Turn 474 into 450 because 45 is a multiple of 9 9 x 5= 45 9 x 50= 45 Therefore 474 would be 450. So, 450 divided by 9 equals 50
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Given the arithmetic sequence an = −3 + 9(n − 1), what is the domain for n?
swat32
I believe that the answer is All integers where n \geq 1
                                               
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Jeff is 18 years older than Joe, and Jeff is also 2 1/2 times as old as Joe. How old is Joe?
Yuri [45]

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First of all, half of 18 is 9, and if you divide 18 by 2.5, it results in 7.2. I hope this helps!

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2 years ago
How can you find the whole when you know part and the percent.
Usimov [2.4K]

An example should make this clear.

If  $50  is 40%   what is the value of the whole amount?

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4 0
3 years ago
A golfer exerts a force of 15.0 N on a golf ball that has a mass of 0.42 kg. What is the golf
Gala2k [10]

Answer:

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Step-by-step explanation:

using the formula force(F)=mass(m)×acceleration(a)

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5 0
3 years ago
Read 2 more answers
Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to
RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

5 0
2 years ago
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