Mass percentage of a solution is the amount of solute present in 100 g of the solution.
Given data:
Mass of solute H2SO4 = 571.3 g
Volume of the solution = 1 lit = 1000 ml
Density of solution = 1.329 g/cm3 = 1.329 g/ml
Calculations:
Mass of the given volume of solution = 1.329 g * 1000 ml/1 ml = 1329 g
Therefore we have:
571.3 g of H2SO4 in 1329 g of the solution
Hence, the amount of H2SO4 in 100 g of solution= 571.3 *100/1329 = 42.987
Mass percentage of H2SO4 (%w/w) is 42.99 %
The equilibrium constant of the reaction is represented by the symbol K. Thus, option C is the correct and accurate statement about the equilibrium constant.
<h3>What is the equilibrium constant?</h3>
The equilibrium constant is a representation of the concentration of the products and the reactants of the reaction that is raised to the powers through their stoichiometry coefficient.
Its value varies and changes at different temperatures and is not always less than 1. The equilibrium constant is the ratio of the coefficient of the products to reactants.
Therefore, option C. equilibrium constant is represented by K is true.
Learn more about the equilibrium constant here:
brainly.com/question/12429748
#SPJ1
Answer:
Manganese: Mn
Explanation:
The elestron configuration would show this is 25 electrons
Atomic number : 25
this electron configuration ends in 
half of the d subshell which is 10
Answer:
Boiling- 212° F melting- 32°F
Explanation:
Socratic helps for you page
